Solve for the first variable in one of the equations, then substitute the result into the other equation.
Y
=
2
y
/3
−
3
x
=
−
y
/3
+
7
Hope this helped!
<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
(-♾, 5) (5, ♾)
Step-by-step explanation:
Answer:
y=4x+11
Step-by-step explanation:
multiply 4 into the parentheses to get y-3=4x+8 then invert -3 so add three to both sides to get rid of it so instead of +8 its +11 so now its y=4x+11 and slope intercept is y=mx+b, so 4 is m, slope, and 11 is b, the y intercept i hope that helps
