Since the number of moles of a substance is the mass divided by the molar mass of the substance, we can just simply multiply the molar mass of magnesium chloride by the number of moles, which is 4.40 in this case.
To find the molar mass, refer to the periodic table for the relative atomic mass of Mg and Cl and add them together. Since there’s 2 chloride ions in MgCl2, double the relative atomic mass of Cl when adding.
24.31 + 35.45x2
=95.21
Now just multiply 95.21 to 4.40mol, which you’ll get 418.9g (corrected to 3 significant figures)
Respuesta:
Yes.
Explicación:
Las teorías se pueden mejorar o modificar a medida que se recopila más información para que la precisión de la predicción sea mayor con el tiempo.
2CH4+O2-> 2CH3OH
A combustion reaction involves only hydrogen, carbon, and oxygen where O2 is always a reactant. So, the only one possible is the one stated above.
Answer:
The equilibrium constant is 9.034.
Explanation:
Every reversible chemical reaction, as in this case, occurs in both directions: the reagents are transformed into products (direct reaction) and the products are transformed back into reagents (
reverse reaction).
The general way in which a reversible reaction can be written is:
aA + bB ⇔ cC + dD
where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients.
The chemical equilibrium is the state in which the direct and indirect reaction have the same reaction rate, and is expressed by a constant Kc. This constant is defined as:
![Kc=\frac{[A]^{a}*[B]^{b} }{[C]^{c} *[D]^{d} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BA%5D%5E%7Ba%7D%2A%5BB%5D%5E%7Bb%7D%20%20%7D%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D)
This constant is equal to the multiplication of the concentrations of the products elevated to their stoichiometric coefficients divided the multiplication of the concentrations of the reactants elevated to their stoichiometric coefficients. In Kc only gases and aqueous solutions come into play and only depends on the temperature.
You have the reaction:
Cl₂(g) + H₂(g) ⇌ 2 HCl(g)
So, in this case, the constant Kc is:
![Kc=\frac{[HCl]^{2} }{[Cl_{2} ]*[H_{2}] }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BHCl%5D%5E%7B2%7D%20%7D%7B%5BCl_%7B2%7D%20%5D%2A%5BH_%7B2%7D%5D%20%7D)
Then:

Kc= 9.034
<u><em>The equilibrium constant is 9.034.</em></u>