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spin [16.1K]
3 years ago
11

What is released when an excited electron returns to a lower energy state?

Chemistry
2 answers:
finlep [7]3 years ago
8 0

Answer: Light is released.

Explanation: Light is released as an electron moves to a lower energy state.

Jobisdone [24]3 years ago
3 0

Answer:

Light

Explanation:

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AlexFokin [52]

Answer:

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16. H20 - Covalent

17. Mn(NO2)2 - Ionic and called Manganese(II) nitrate

18. HgO - Ionic

19. Li3N - Covalent

7 0
1 year ago
Select all of the following statements that are incorrect.
lesantik [10]
A and c are incorrect
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3 years ago
What is unique about the nitrogen family
ankoles [38]
Nitrogen molecule is diatomic, whereas other elements form tetraatomic molecules.
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3 years ago
Read 2 more answers
A solution is prepared by dissolving 20.1 g of MgCl2 with the addition of 157.0 mL of water (density of water is 1.00g/cm3). The
Nezavi [6.7K]

Answer:

1.3 M.

Explanation:

  • We need to calculate the mass of the solution:

mass of the solution = mass of MgCl₂ + mass of water

mass of MgCl₂ = 20.1 g.

mass of water = d.V = (157.0 mL)(1.0 g/cm³) = 157.0 g.

∴ mass of the solution = mass of MgCl₂ + mass of water = 20.1 g + 157.0 g = 177.1 g.

  • Now, we can get the volume of the solution:

V of the solution = (mass of the solution)/(density of the solution) = (177.1 g)/(1.089 g/cm³) = 162.62 mL = 0.163 L.

Molarity is the no. of moles of solute dissolved in a 1.0 L of the solution.

M = (no. of moles of MgCl₂) / (Volume of the solution (L)).

<em>∴ M = (mass/molar mass)of MgCl₂ / (Volume of the solution (L)) =</em> (20.1 g/95.211 g/mol) / (0.163 L) = <em>1.29 M ≅ 1.3 M.</em>

6 0
3 years ago
Need asap thank you
cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

6 0
2 years ago
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