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3 years ago

What is released when an excited electron returns to a lower energy state?

Chemistry

2 answers:

finlep [7]3 years ago

8 0

Answer: Light is released.

Explanation: Light is released as an electron moves to a lower energy state.

Jobisdone [24]3 years ago

3 0

Answer:

Light

Explanation:

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Sulfurous Acid, H2SO3, is a diprotic acid, with the following acid dissociation constants: Ka1 = 1.4 × 10-2 Ka2 = 6.7 × 10-8 Wha

Colt1911 [192]

Answer:

Kb = 7.1 x 10⁻¹³

Explanation:

Ka x Kb = Kw => Kb = 1 x 10⁻¹⁴/1.4 x 10⁻² = 7.1 x 10⁻¹³

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3 years ago

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Electrons are capable of emmiting engery in the form of light at very narrow ranges of wavelengths. these wavelengths can be mea

sukhopar [10]

C) energy level

Looking at quantum mechanics, we see that electrons exist at certain energy levels. When they get excited, they’ll jump from one energy state to a higher energy state and down. We can the. Look at the color it admits and determine what the energy level is.

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3 years ago

How many valence electrons are in Tc

mixer [17]

Tc is Technetium, and it has an atomic number of 43. Its atomic configuration is [Kr] 5s(1) 4d(5) [I'm on my phone so I can't do numbers on shoulders, pretend that 1 and 5 are on the s and d's shoulder]
The outside most ring is the 4d(5), and the d orbital can hold ten electrons.
Valence electrons are electrons, in you could say the outside ring that isn't filled, the extra ones. In this case, there are 5.

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3 years ago

What is the concentration of a solution made with 0.150 moles of KOH in 400.0 mL of solution?

otez555 [7]

Answer:

$concentration = \frac{0.15}{0.4}=0.375 mol/L$

Explanation:

Concentration: i is defined as the mole per litre.

$concentration = \frac{mole}{volume in L}$

mole=0.15

volume=400 ml=0.4 litre

$concentration = \frac{0.15}{0.4}=0.375 mol/L$

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3 years ago

Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL

wlad13 [49]

Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$

Molarity is expressed in units $\frac{moles}{liter}$ .

<h3>Molarity of solution of sodium sulfate.</h3>

In this case, you have:

number of moles of sodium sulfate= $5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles$ (being 142 g/mole the molar mass of sodiums sulfate)
volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

$Molarity=\frac{0.0366 moles}{0.5 L}$

Solving:

Molarity= 0.0732 $\frac{moles}{liter}$

Finally, the molarity of solution of sodium sulfate is 0.0732 $\frac{moles}{liter}$ .

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2 years ago