Answer:
Only two elements are liquid at standard conditions for temperature and pressure: mercury and bromine. Four more elements have melting points slightly above room temperature: francium, caesium, gallium and rubidium.
Explanation:
Respuesta:
2400 mL
Explicación:
Paso 1: Información dada
- Volumen de solución: 3 L (3000 mL)
- Concentración de naranja: 20 % v/v
Paso 2: Calcular el volumen de naranja
La concentración de naranja es de 20 % v/v, es decir, cada 100 mL de solución hay 20 mL de naranja.
3000 mL Sol × 20 mL Naranja/100 mL Solución = 600 mL Naranja
Paso 3: Calcular el volumn de agua
El volumen de soluciónes igual a la suma de los volúmenes de naranja y agua.
VSolución = VNaranja + VAgua
VAgua = VSolución - VNaranja
VAgua = 3000 mL - 600 mL = 2400 mL
Answer:
C5H6N2O3
Explanation:
First the empirical formulas
C= 41.8÷12= 2.48
H= 4.7÷1= 4.7
O= 37.3÷ 16= 2.33
N= 16.3÷14 = 1.16
Divide by the smallest
C= 3.48/1.16=3
H= 4.7/1.16=4.1
O= 2.33/1.16=2
N= 1.16/1.16=1
Therefore empirical formula = C3H4NO2
To calculate molecular formula for osmotic pressure,
π= cRT
Or
π=cgRT/M where cg is in g/liter & T is temperature in Kelvin. Thus
π= (7.480*0.0821*300)/ M
M= 184.23/1.43
M= 128.83
To find molecular Formula
Molecular Mass= (empirical mass)n
128.83= (C3H4NO2)n
128.83= 86n
n= 1.5
Therefore the molecular formula
(C3H4NO2)1.5
= C4.5H6N1.5O3
Approximately
C5H6N2O3
