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xz_007 [3.2K]
3 years ago
5

1. Which expression is equivalent to c+C -0.44?

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

I think B but Im not 100% sure

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Kim has worked in the tech industry for some time and would like to start consulting. In opening her new business, she will need
zimovet [89]
Cost of 3 laptops
3×546.78
=1,640.34
Cost of 2 desktop computer
2×1,255.99
=2,511.98
Cost of fax machine
125.99
Total cost
(1,640.34+2,511.98+125.99)
=4,278.31
So Kim will need an additional 778.31 to start her business
4,278.31−3,500
=778.31
7 0
3 years ago
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3. Connor works part-time at Tom Thumb. On Wednesday, Thursday and Friday, he
erik [133]
Wednesday he made $29
Thursday he made $22
Friday he made $34
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3 years ago
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The value of a dvd player decreases by 60% each year. If you purchased this dvd player today for $180, how much would the player
Volgvan
The formula is
A=p (1-r)^t
A future value?
P present value 180
R rate of decreases 0.6
T time 2 years
A=180×(1−0.6)^(2)
A=180×(0.4)^(2)
A=28.8
3 0
3 years ago
Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation
alukav5142 [94]

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

8x - 10y = 20

8x +12y = 6

Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

4 0
3 years ago
A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e
ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

7 0
3 years ago
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