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charle [14.2K]
2 years ago
13

1. List the 3 major skeletal cartilages.

Physics
2 answers:
zvonat [6]2 years ago
4 0
The 3 major skeletal cartilages are hyaline ,elastic, and fibrocartilage.  hope this helps
il63 [147K]2 years ago
3 0
Hyaline, elastic, & fibrocartilage!
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When hiking at altitude, the air pressure drops to 825,000Pa. Solve the force that site exerts against the side of a rectangular
OLga [1]

Answer:

The force is 1237500N

Explanation:

We can apply the following expression

pressure=\frac{Force}{Area}

To find the area of rectangular tent wall:

Area=length *width\\Area=2.00m*0.750m\\Area=1.5m^{2}

Now to find the force:

pressure=825,000pa

pressure=\frac{Force}{Area}

Force=pressure*Area\\Force=825000pa*1.5m^{2} \\Force=1237500N

7 0
2 years ago
Fnet = fa + ff or fnet = fa - ff
skelet666 [1.2K]

Answer:first of all what is your question and i can give and example which is Use them when you have 2 forces named Fa & FF or Fg & Ff acting in opposite directions on an object and you need to know the resultant of your 2 forces.

Explanation:

i searched it up

5 0
2 years ago
How are motors and generators different?
saw5 [17]
A generator converts mechanical energy into electrical energy, while a motor does the opposite - it converts electrical energy into mechanical energy
4 0
3 years ago
During each cycle, a refrigerator ejects 610 kJ of energy to a high-temperature reservoir, and takes in 505 kJ of energy from a
jenyasd209 [6]

Answer

A. the work done on the refrigerant in each cycle is 105kJ

B the coefficient of performance of the refrigerator is 4.8

Explanation

Given data

Work done at high temperature T2 Qh=610kJ

Work done at low temperature T1 Ql=505kJ

We know that the net work done by the refrigerator is expressed as

Wnet= Qh-Ql

=610-505

=105kJ

Also we know that the coefficient of performance is expressed as

COP= Ql/Wnet

COP= 505/105

= 4.8

8 0
2 years ago
Coasting due west on your bicycle at 8 m/s, you encounter a sandy patch of road 7.2m
jeka57 [31]

Answer:

V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s     average speed

t = 7.2 / 7.25 = .993 sec      time to cross patch

a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2     or 1.5 m/s^2

8 0
2 years ago
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