Answer:
Myocardium. That is the type. (srry i was in a rush hope this helps)
Explanation:
1.
We use the equation
h = 
, where
h is the height traveled,
g is the acceleration due to gravity and
t is the time taken to reach height h.
We can now calculate t to be
= 0.495 s
Let v be the initial velocity of the player.
The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.
v = 9.81 m/s^2 x 0.495 s = 4.85 m/s
2.
The player takes 0.3 s to increase his velocity from 0 m/s to 4.85 m/s. So his average accelaration is
4.85 m/s / 0.3 s = 16.2 m/s^2
Answer:
2.26 s
Explanation:
The following data were obtained from the question:
Height (h) = 25 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =..?
The time taken for the egg to hit the floor can be obtained as illustrated below:
h = ½gt²
25 = ½ × 9.8 × t²
25 = 4.9 × t²
Divide both side by 4.9
t² = 25 / 4.9
Take the square root of both side
t = √(25 / 4.9)
t = 2.26 s
Thus, it will take 2.26 s for the egg to hit the floor.
Answer:
c
Explanation:
though c is wider it has more water.
Answer:
Explanation:
We shall first calculate the velocity at height h = 575 m .
acceleration a = 2.2 m /s²
v² = u² + 2 a s
u is initial velocity , v is final velocity , s is height achieved
v² = 0 + 2 x 2.2 x 575
v = 50.3 m /s
After 575 m , rocket moves under free fall so g will act on it downwards
If it travels further by height H
from the relation
v² = u² - 2 g H
v = 0 , u = 50.3 m /s
H = ?
0 = 50.3² - 2 x 9.8 H
H = 129.08 m
Total height attained by rocket
= 575 + 129.08
= 704.08 m .
