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Westkost [7]
3 years ago
9

Why are you able to observe the Doppler Effect with sound waves on Earth but not light waves?

Physics
1 answer:
professor190 [17]3 years ago
4 0
The doppler effect is when waves’ wavelengths get squished when the source is moving toward you or stretched when the source is moving away from you. it can be observed with sound waves but not light waves because the speed of light is just too fast, meaning that we can’t move toward or away fast enough. (also some stuff with relativity).
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How does the current in a series circuit compare
alexandr402 [8]
The amount of current is the same through any component in a series circuit. Resistance: The total resistance of any series circuit is equal to the sum of the individual resistances. Voltage: The supply voltage in a series circuit is equal to the sum of the individual voltage drops.
8 0
3 years ago
Describe how sound at a concert is different from the front row and the back.
satela [25.4K]
In the front is where the bass of everything comes from so it’s generally louder up there and toward the back there’s not as much bass to the music more just hearing the singer and other people screaming
7 0
3 years ago
An electric motor rotating a workshop grinding wheel at a rate of 1.31 ✕ 102 rev/min is switched off. Assume the wheel has a con
antoniya [11.8K]

(a) 4.03 s

The initial angular velocity of the wheel is

\omega_i = 1.31 \cdot 10^2 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=13.7 rad/s

The angular acceleration of the wheel is

\alpha = -3.40 rad/s^2

negative since it is a deceleration.

The angular acceleration can be also written as

\alpha = \frac{\omega_f - \omega_i}{t}

where

\omega_f = 0 is the final angular velocity (the wheel comes to a stop)

t is the time it takes for the wheel to stop

Solving for t, we find

t=\frac{\omega_f - \omega_i }{\alpha}=\frac{0-13.7 rad/s}{-3.40 rad/s^2}=4.03 s

(b) 27.6 rad

The angular displacement of the wheel in angular accelerated motion is given by

\theta= \omega_i t + \frac{1}{2}\alpha t^2

where we have

\omega_i=13.7 rad/s is the initial angular velocity

\alpha = -3.40 rad/s^2 is the angular acceleration

t = 4.03 s is the total time of the motion

Substituting numbers, we find

\theta= (13.7 rad/s)(4.03 s) + \frac{1}{2}(-3.40 rad/s^2)(4.03 s)^2=27.6 rad

6 0
3 years ago
Match each scenario to the form of energy it represents.
Pachacha [2.7K]
<span>Correct pairs:

a man jogging in the park --> motion energy (the energy is the kinetic energy of the man, moving with speed v)

a fully charged camera battery --> electric potential energy (the battery is fully charged, so it can deliver electrical energy when the camera is turned on)

a stove burner that’s turned on --> radiant energy (the stove burner emits energy by radiation)

an apple on a tree --> gravitational potential energy (when the apple is on the tree, it has gravitational potential energy equal to U=mgh, where m is the apple's mass and h its height from the ground)
</span><span>
</span>
5 0
3 years ago
I’m in the middle of a test right now. If anybody knows this can they help
babymother [125]

Answer:

C

Explanation:

momentum = mass ×velocity

A. mv = 200

B. mv = 300

C. mv= 400

D. mv= 200

highest is C.

6 0
3 years ago
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