What is the answer to this equation? M¹u¹ + M²u² = M¹V¹ + M¹V²

While on the moon, the Apollo astronauts enjoyed the effects of a gravity much smaller than that on Earth. If Neil Armstrong jum

Juliette [100K]

Answer:

The gravitational acceleration experienced was of 1.63m/s².

Explanation:

We know, from the kinematics equations of vertical motion that:

$v^{2} =v_0^2-2gy$

Solving for g, we get:

$g=-\frac{v^2-v_0^2}{2y}$

Since the final speed is zero, because Neil Armstrong came to a stop in his maximum height, we obtain:

$g=\frac{v_0^2}{2y}$

Finally, we plug in the given values of the initial speed and the maximum height:

$g=\frac{(1.51m/s)^2}{2(0.700m)}=1.63m/s^2$

This means that the gravitational acceleration experienced by Neil Armstrong in the moon, was of 1.63m/s².

6 0

2 years ago

According to the Guinness Book of World Records (1999) the highest rotary speed ever attained was 2010 m/s (4500 mph) The rotati

Zinaida [17]

Answer:

a. 2.645 * 10^7 m/s^2

b. 2.645 * 10^4 N

Explanation:

Parameters given:

Velocity of rod = 2010m/s

Length of rod = 15.3cm = 0.153m

Mass of object placed at the end of the rod = 1g = 0.001kg

a. Centripetal acceleration is given as:

a = (v*v)/r

Where v = velocity

r = radius of curvature.

The radius of curvature in this case is equal to the length of the rod, since the rod makes the circular path of the motion.

Hence, centripetal acceleration at the end of the rod:

a = (2010*2010)/(0.153)

a = 26432156.86 m/s^2 = 2.64 * 10^7 m/s

b. The force needed to hold the object at the end of the rod is equal to the centripetal force at the end of the rod. Centripetal force is given as:

F = ma = (m*v*v)/r

Where a = centripetal acceleration

F = 0.001 * 2.64 * 10^7

F = 2.64 * 10^4N

7 0

2 years ago

A 10 kg mass stretches a spring 70 cm in equilibrium. Suppose a 2 kg mass is attached to the spring, initially displaced 25 cm b

NARA [144]

Answer:

Explanation:

1. Find spring constant k. From a free body diagram, you will get the forces on the 10 kg mass, with a displacement d. It will be gravity pulling the mass down and the spring force pulling the mass up. The 10 kg mass is in equilibrium. The resulting equation will be:

$F = m_1a = kd - m_1g = 0 => m_1g = kd => k = \frac{m_1g}{d}$