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Gekata [30.6K]
3 years ago
6

What is the answer to this equation? M¹u¹ + M²u² = M¹V¹ + M¹V²​

Physics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

m²=m¹

Explanation:

m¹v¹ + m²v² = m¹ v¹+m¹v²

m²v²= m¹v²

m²v²/v² = m¹

m² = m¹

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An x-ray beam of wavelength 1.4×10−10m makes an angle of 20° with a set of planes in a crystal(the Bragg angle)causing first ord
Gnom [1K]

Answer:

Second order line appears at 43.33° Bragg angle.

Explanation:

When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.

The Bragg's diffraction equation is :

n\lambda=2d\sin\theta      .....(1)

Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

Given :

Wavelength, λ = 1.4 x 10⁻¹⁰ m

Bragg's angle, θ = 20°

Order of constructive interference, n =1

Substitute these value in equation (1).

1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}

\sin\theta_{1} =0.68

<em>θ₁ </em>= 43.33°

4 0
3 years ago
Two light bulbs have resistances of 400 Ω and 800 ΩThe two light bulbs are connected in series across a 120- V line. Find the cu
Natasha2012 [34]

1) Current in each bulb: 0.1 A

The two light bulbs are connected in series, this means that their equivalent resistance is just the sum of the two resistances:

R_{eq}=R_1 + R_2 = 400 \Omega + 800 \Omega=1200 \Omega

And so, the current through the circuit is (using Ohm's law):

I=\frac{V}{R_{eq}}=\frac{120 V}{1200 \Omega}=0.1 A

And since the two bulbs are connected in series, the current through each bulb is the same.

2) 4 W and 8 W

The power dissipated by each bulb is given by the formula:

P=I^2 R

where I is the current and R is the resistance.

For the first bulb:

P_1 = (0.1 A)^2 (400 \Omega)=4 W

For the second bulb:

P_1 = (0.1 A)^2 (800 \Omega)=8 W

3) 12 W

The total power dissipated in both bulbs is simply the sum of the power dissipated by each bulb, so:

P_{tot} = P_1 + P_2 = 4 W + 8 W=12 W

3 0
3 years ago
Please help with these questions
lord [1]
When do you gotta turn it in?
8 0
2 years ago
How much force must you apply to give the go cart an acceleration of 0.9m/s^2
qaws [65]
It's dependent on the mass. You can fimd the force needed using the formula F = ma. Where F is force, m is mass of the cart and a is the acceleration (0.9m/s^2). The heavier it is the more force you are going to need. Remember unit of force is N
5 0
3 years ago
A ball has 116.62 J of gravitational potential energy at a height of 85 m. What is the mass of the ball?
SashulF [63]

Answer:0.14 kg

Explanation:

Gravitational potential energy=pe=116.62J

Height=h=85m

Acceleration due to gravity=g=9.8m/s^2

Mass=m

Pe=m x g x h

116.62=m x 9.8 x 85

116.62=m x 833

Divide both sides by 833

116.62 ➗ 833=(m x 833) ➗ 833

0.14=m

Mass=0.14 kg

8 0
4 years ago
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