Refer to the diagram shown below.
Let x = distance of the base of the ladder from the base of the hill.
By definition,
sin(75°) = x/15
x = 75*cos(75°) = 3.882 ft
Answer:
The distance between the base of the hill and the base of the ladder is 3.9 ft (nearest tenth)
Answer:
(a) 
(b) 
(c) 
Explanation:
Given data
x(t)=αt²-βt³
α=1.53m/s²
β=0.0480m/s³
First we need to find distance x at these time so
x(t)=1.53t²-0.0480t³
at t=0
x(0)=1.53(0)²-0.0480(0)³=0m
at t=2
x(2)=1.53(2)²-0.0480(2)³=5.736m
at t=4s
x(4)=1.53(4)²-0.0480(4)³=21.408 m
For(a) Average velocity at t=0s to t=2s
The average velocity is given as
Vavg=Δx/Δt
For(b) Average velocity at t=0s to t=4s
The average velocity is given as
Vavg=Δx/Δt
For(c) Average velocity at t=2s to t=4s
The average velocity is given as
Vavg=Δx/Δt
Navigators used astrolabes to calculate positions of the sun and stars.
It can never be shorter than a component - magnitude of a vector is the square root of the sum of the components squared, and a square function never produces a negative number. However, it can be the same size as it's component, if that component is the only one.
