The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
20%
Step-by-step explanation:
You have to do 5/25, giving you 20%.
The system should look like this:
eh + b = 243
eh - b = 109
Answer:
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Step-by-step explanation:
Answer:
Denote 3 consecutive numbers as: (n-1), n, (n+1)
=> n - 1 + n + n + 1 = 498
=> 3*n = 498
=> n = 166
=> n + 1 = 166 + 1 = 167
=> 3rd number is 167
