Answer:
Step-by-step explanation:
Left
As near as I can tell, the question is x^(1/2) * x^(1/2) = The bases are the same, so all you do is add the powers.
x^(1/2 + 1/2) = x^1 which is just x.
Right
The is another one where the work is hard to show. The numerator (m) of the fraction is the power and the denominator (n) is the root. That sentence is all the work there is.
So you would write ![\sqrt[m]{x^{n} } = x^{\frac{m}{n} }](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5E%7Bn%7D%20%7D%20%3D%20x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%20%7D)
Answer:
i think that is 4
Step-by-step explanation:
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You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.
Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.
2(4) + 4k - 9 = (4)(4) - (4) + 1
Then 8 + 4k - 9 = 16 - 4 + 1, or 4k - 1 = 13. Then 4k = 14, and k = 14/4, or (after reduction) k = 7/2
If the parameter k equals 7/2, then x = 4 is a solution to the given equation.
To check this out further, start with the proposed solution x = 5 and find k.
I am not sure it is 2i think
