Answer:
not completely sure but I think it's it's 13.4
Answer:
There is a 2/3 probability that the other side is also black.
Step-by-step explanation:
Here let B1: Event of picking a card that has a black side
B2: Event of picking a card that has BOTH black side.
Now, by the CONDITIONAL PROBABILITY:

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.
⇒ P (B1 ∩ B2) = 1 /3
Also, Out if total 6 sides of cards, 3 are BLACK from one side.
⇒ P (B1 ) = 3 /6 = 1/2
Putting these values in the formula, we get:

⇒ P (B2 / B1) = 2/3
Hence, there is a 2/3 probability that the other side is also black.
Answer:
Evan is correct
Step-by-step explanation:
To find this answer, we can use the formula A=PxW
A=Part, P=Percentage, W=Whole
We can fill in the numbers we know and leave blank (with the variable) the numbers we want to find out
In this scenario, we want to find out if 25 is 125% of 29
So we can use this formula and do the equation like this:
A=1.25x20
This gets us to 25
So Evan is correct!
Hope this helps and please award brainliest if possible!
Answer:
20=4 weeks
40=8 weeks
60=12 weeks
80=16 weeks
Hope I helped :)
Answer:
We can conclude that the result is significant and production differ in cost variance.
Step-by-step explanation:
Given :
n1 = 16
n2 = 16
s1² = 5.7
s2² = 2.8
α = 0.10
H0 : σ1² = σ2²
H1 : σ1² ≠ σ2²
The test statistic :
Ftest = s1² / s2² =
Ftest = 5.7 / 2.8
Ftest = 2.036
Using the Pvalue from Fratio calculator :
df numerator = 16 - 1 = 15
df denominator = 16 - 1 = 15
Pvalue(2.036, 15, 15) = 0.0898
Pvalue = 0.0898
Since the Pvalue is < α ; We can conclude that the result is significant and production differ in cost variance.