Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108
Answer:
Here's what I've found
Explanation:
Refer to the attachment !
Whdhrntggmtkasbudubbffjtt
A force or a type of friction?
Force: Resistance--> If you go swimming, you feel the water pushing against you, making it harder to walk in water and even to swim unless you are doggy pattling or front strokes. Resistance is a force going against a solid object.
Friction: Fluid friction which is friction that occurs after a solid object travels through a liquid or gas
