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2 years ago

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The isomers butane and methylpropane differ in their 1) mo;ecular formulas 2) structural formulas 3) total number of atoms per m

olecule 4) total number of bonds per molecule

1 answer:

docker41 [41]2 years ago

7 0

Answer:

Structural formulas

Explanation:

I know cause i just did it

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Based on the results from this experiment, predict whether some of the following combinations of compounds would precipitate or

iren [92.7K]

Answer:

* No precipitate: $LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

* Precipitate: $3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

* Precipitate: $MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Explanation:

Hello!

In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:

a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:

$LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)$

b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:

$3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)$

c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:

$MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)$

Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.

Best regards!

6 0

2 years ago

A 40.27 g sample of a substance is initially at 24.8 °c. after absorbing 2099 j of heat, the temperature of the substance is 148

Darina [25.2K]

Q = mCΔT
Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp

2099 J = (40.27g)(C)(148.5 - 24.8) = .421 J / gram K

6 0

2 years ago

What is the term for a solid that forms when two solutions are mixed? a precipitate a gas a suspension a solution

SashulF [63]

When a solid forms with two solutions are mixed it is a precipitate

6 0

2 years ago

Read 2 more answers

A standard 1.00 kg mass is to be cut from a bar of steel having an equilateral triangular cross section with sides equal to 2.50

Elden [556K]

Answer:

The section of the bar is 2.92 inches.

Explanation:

Mass of the steel cut ,m = 1.00 kg = 1000 g

Volume of the steel bar = V = Area × height

Height of the of the section of bar = h

Area of Equilateral triangular = $\frac{\sqrt{3}}{4}a^2$

a = 2.50 inches

Cross sectional area of the steel mass = A

$A=\frac{\sqrt{3}}{4}(2.50 inches)^2=2.71 inches^2$

$V = 2.71 inches^2\times h$

Density of the steel = d = $7.70 g/cm^3$

$1cm^3 = 0.0610237 inches^3$

$d=\frac{m}{v}$

$\frac{7.70 g}{0.0610237 inches^3}=\frac{ 1000 g}{2.71 inches^2\times h}$

$h=\frac{ 1000 g\times 0.0610237 inches^3}{2.71 inches^2\times 7.70 g}$

h = 2.92 inches

The section of the bar is 2.92 inches.

3 0

2 years ago

What is the name of the compound Ca(NO3)2 ?

natulia [17]

Answer: B) calcium nitrate

5 0

2 years ago