Ask question

Ask question

All categories

2 years ago

15

The isomers butane and methylpropane differ in their 1) mo;ecular formulas 2) structural formulas 3) total number of atoms per m

olecule 4) total number of bonds per molecule

1 answer:

docker41 [41]2 years ago

7 0

Answer:

Structural formulas

Explanation:

I know cause i just did it

You might be interested in

A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percentage, the student measures out 5.84 grams o

julsineya [31]

Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

$Number \, of \, moles, n = \frac{Mass}{Molar \ mass} = \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl$

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

3 0

3 years ago

Which force is most responsible for slowing a bicycle down when the brakes are applied

Leya [2.2K]

Friction <span>is most responsible for slowing a bicycle down when the brakes are applied</span>

7 0

2 years ago

Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570

Andrews [41]

x = 1.01

Explanation:

Given equation:

y = 1.2345x – 0.6789

y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

Since we have been given y = 0.570

y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

since y = 0.570

0.57 = 1.2345x – 0.6789

add 0.6789 to both sides;

0.57 + 0.6789 = 1.2345x – 0.6789 + 0.6789

1.2489‬ = 1.2345x

Divide both sides by 1.2345

$\frac{1.2489}{ 1.2345} = \frac{ 1.2345x }{ 1.2345}$

x = 1.01

learn more:

Equations brainly.com/question/9045597

#learnwithBrainly

7 0

2 years ago

A 3.50 g sample of an unknown compound containing only C , H , and O combusts in an oxygen‑rich environment. When the products h

statuscvo [17]

Explanation:

First, calculate the moles of $CO_{2}$ using ideal gas equation as follows.

PV = nRT

or, n = $\frac{PV}{RT}$

= $\frac{1 atm \times 4.41 ml}{0.0821 Latm/mol K \times 293 K}$ (as 1 bar = 1 atm (approx))

= 0.183 mol

As, Density = $\frac{mass}{volume}$

Hence, mass of water will be as follows.

Density = $\frac{mass}{volume}$

0.998 g/ml = $\frac{mass}{3.26 ml}$

mass = 3.25 g

Similarly, calculate the moles of water as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{3.25 g}{18.02 g/mol}$

= 0.180 mol

Moles of hydrogen = $0.180 \times 2$ = 0.36 mol

Now, mass of carbon will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

0.183 mol = $\frac{mass}{12 g/mol}$

= 2.19 g

Therefore, mass of oxygen will be as follows.

Mass of O = mass of sample - (mass of C + mass of H)

= 3.50 g - (2.19 g + 0.36 g)

= 0.95 g

Therefore, moles of oxygen will be as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{0.95 g}{16 g/mol}$

= 0.059 mol

Now, diving number of moles of each element of the compound by smallest no. of moles as follows.

C H O

No. of moles: 0.183 0.36 0.059

On dividing: 3.1 6.1 1

Therefore, empirical formula of the given compound is $C_{3}H_{6}O$ .

Thus, we can conclude that empirical formula of the given compound is $C_{3}H_{6}O$ .

6 0

3 years ago

Trường hợp nào sau đây là chất tinh khiết

Verdich [7]

Answer:

where????

Explanation:

nasaan yung pag pipilian???

6 0

2 years ago

Read 2 more answers