Answer:
F₄ = 29.819 N
Explanation:
Given
F₁ = (- 25*Cos 50° i + 25*Sin 50° j + 0 k) N
F₂ = (12*Cos 50° i + 12*Sin 50° j + 0 k) N
F₃ = (0 i + 0 j + 4 k) N
Then we have
F₁ + F₂ + F₃ + F₄ = 0
⇒ F₄ = - (F₁ + F₂ + F₃)
⇒ F₄ = - ((- 25*Cos 50° i + 25*Sin 50° j) N + (12*Cos 50° i + 12*Sin 50° j) N + (4 k) N) = (13*Cos 50° i - 37*Sin 50° j - 4 k) N
The magnitude of the force will be
F₄ = √((13*Cos 50°)² + (- 37*Sin 50°)² + (- 4)²) N = 29.819 N
Answer:
- 0.5 m/s
Explanation:
(1) Acceleration = change in velocity / time
(2) Change in velocity = (Final velocity - Initial velocity)
We know:
acceleration = 1.5 m/s/s
time = 5 seconds
final velocity = 7 m/s
x = initial velocity)
1.5 = ( 7 - x ) / 5
1.5 x 5 = ( 7 - x )
7.5 = 7 - x
x = -0.5 m/s
You can check the answer by plugging in the values to equation (1).
Answer:
I think A. I had a similar question
Explanation:
Answer:
The time taken by the car to get to the other side of an intersection is, t = 4.9 s
Explanation:
Given data,
The acceleration of the car, a = 2.5 m/s²
The initial velocity of the car, u = 0
The distance traveled, s = 30 m
Using the II equations of motion,
<em> S = ut + ½ at²</em>
Therefore,
t = √(2S/a) ( since u = 0)
Substituting the values
t = √(2 x 30 / 2.5)
= 4.9 s
Hence, the time taken by the car to get to the other side of an intersection is, t = 4.9 s
Answer:
The answer to your question is 56 ml
Explanation:
Data
V1 = 97 ml
P1 = 130 kPa
V2 = ?
P2 = 225 kPa
Formula
Use Boyle's law to solve this problem because it relates to the volume and the pressure.
V1P1 = V2P2
Solve for V2
V2 = (V1P1) / P2
Substitution
V2 = (97 x 130) / 225
Simplification
V2 = 12610 / 225
Result
V2 = 56 ml