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babymother [125]
3 years ago
15

If 1.00 kilograms of coal is burned, approximately 3.00 x 107 joules (J) of energy is released. How many tons of coal, when burn

ed, would produce approximately 9.00 x 1016 J?
Physics
2 answers:
Marrrta [24]3 years ago
5 0

Answer:

3.00\times10^{6}\,tons

Explanation:

We can resolve this problem using a proportion because the ratio tons burned and energy produced is constant, using x for tons burned of coal to produce 9.00\times10^{16}J:

\frac{x}{9.00\times10^{16}J}=\frac{1.00\,kg}{3.00\times10^{7}J}

solving the proportion:

x*3.00\times10^{7}J=1.00\,kg*9.00\times10^{16}J

\frac{x*\cancel{3.00\times10^{7}J}}{\cancel{3.00\times10^{7}J}}=\frac{1.00\,kg*9.00\times10^{16}J}{3.00\times10^{7}J}

x=\frac{9.00\times10^{16}kg*\cancel{J}}{3.00\times10^{7}\cancel{J}}=3.00\times10^{9}\,kg

Now we have the answer but in kilograms we should convert this knowing that 1 ton = 1000 kg:

3.00\times10^{9}\,kg=3.00\times10^{9}\,\cancel{kg}*\frac{1\,ton}{1000\,\cancel{kg}}

3.00\times10^{9}\,kg=3.00\times10^{6}\,tons

andrezito [222]3 years ago
3 0

Answer:

3.3 x 106 tons

Explanation:

Since you know that E = mc2, and both equations possess the constant speed of light, set the two equations as equivalencies. For instance, E1/m1 = E2/m2. Solve for m2.

Took the test and got it correct

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Answer

given,

time  = 10 s

ship's speed = 5 Km/h

F = m a

a is the acceleration and m is mass.

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F₁ is constant acceleration is also a constant.

Δv₁ = 5 x 0.278

Δv₁ = 1.39 m/s

a_1=\dfrac{1.39}{10}

a₁ = 0.139 m/s²

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a₃ = a₂ + a₁

0.5282 = a₂ + 0.139

a₂=0.3892 m²/s

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F₂/F₁

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4 years ago
A lightbulb is rated by the power that it dissipates when connected to a given voltage. For a lightbulb connected to 120 V house
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Answer:

Increases, increases

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Recall that power is given by P= V^2/R where;

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We can see that power and resistance are inversely related hence decreasing the resistance increases the power output of the lightbulb.

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A parallel-plate capacitor has square plates that are 8.00cm on each side and 4.20mm apart. The space between the plates is comp
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Answer:

U=1.29\times 10^{-7}\ J

Explanation:

Given that

a= 8 cm (square)

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d= 4.2 mm

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d₂=2.1 mm  , K₂=2.6

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