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3 years ago

What is the potential at a distance of 5. 0 ? 10-10 m from a nucleus of charge 50e?

Physics

1 answer:

uranmaximum [27]3 years ago

8 0

The electric potential at a distance from a nucleus of charge 50e is 144 Volts.

<h3>What is electric potential?</h3>

The potential is the work done by the test charge to move it from infinity to a particular point.

The potential is given by the relation

V = kQ / r

The distance of a point from the nucleus is 5.0 × 10⁻¹⁰ m and the charge on the nucleus is 50 e = 50 × 1.9 × 10⁻¹⁹ C.

k = 9 × 10⁹ kg-m²/s²-C²

Here, Q is the charge, r is the distance and k is the constant.

Substituting the value into the equation and solving, we get

V = 144 Volts

Thus, the potential at a distance from a nucleus of charge 50e is 144 Volts.

Learn more about electric potential.

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4 years ago

You move a 25 N object 5.0 meters. How much energy did you transformed?

lilavasa [31]

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3 years ago

The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t

jek_recluse [69]

Answer:

$e=3367.2J$

% $e=1.43$ %

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

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Since the speedometer is only accurate to within 0.1km/h the experimental speed is

$v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s$

Knowing that we can calculate Kinetic energy for the real and experimental speed

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Now, the potential error in her calculated kinetic energy is:

$e=E_{r}-E_{e}=(234023-230656)J=3367.2J$

% $e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43$ %

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4 years ago