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3 years ago

Which of the following is the smaller atom: magnesium or chlorine?

Chemistry

2 answers:

TiliK225 [7]3 years ago

4 0

Answer: Chlorine

Explanation: Since chlorine's 17 protons are greater than magnesium's 12 protons, chlorine will have a greater effective nuclear charge to draw chlorine's valence electrons closer to the nucleus and, thus, chlorine is expected to have the smaller atomic radius, while magnesium with the lower effective nuclear charge is expected to have the larger atomic radius.

Aleks04 [339]3 years ago

3 0

Answer:

Chlorine atoms are smaller

Explanation:

Magnesium have more electrons than chlorine.

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Nitrogen dioxide is a red-brown gas that is responsible for the color of photochemical smog. What is the volume of 1 mol of nitr

Ray Of Light [21]

B ideal gas has a volume of 22.4

5 0

3 years ago

HNO3 + H2SO4 + NO

77julia77 [94]

Explanation:

The two half equations are;

3e + HNO3 → NO

S→ H2SO4 + 6e

When balancing half equations, we have to make sure the number of electrons gained is equal to the number of electrons lost.

Which factor will you use for the top equation?

We multiply by 2 to make the number of electrons = 6e

Which factor will you use for the bottom equation?

We multiply by 1 to make the number of electrons = 6e

3 0

3 years ago

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Iteru [2.4K]

Answer:

The mass of the products left in the test tube will be less than that of the original reactants.

Explanation

The equation for the reaction is

Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

1.0 3.0 3.9 0.1

Assume you started with 1.0 g of Mg.

It will react with 3.0 g of HCl to form 3.9 g of MgCl2 and 0.1 g of H2

Mass of reactants = mass of products

1.0 g + 3.0 g = 3.9 g + 0.1 g

4.0 g = 4.0 g

The Law of Conservation of Mass is obeyed.

However, your test tube and its contents will weigh 0.1 g less than it did before the reaction.

Does that contradict the Law of Conservation of Mass? It does not.

One of the products was the gas, hydrogen, and it escaped from the test tube. You weren't measuring all the products, so test tube and its contents weighed less than before.

7 0

3 years ago

When 0.230 g of sodium metal is added to an excess of hydrochloric acid, 2390 J of heat are produced. What is the enthalpy of th

Dmitriy789 [7]

Answer:

ΔHrxn = 239 kj/mol

Explanation:

Given data:

Mass of sodium = 0.230 g

Heat produced = 2390 J

Solution:

Chemical equation:

2Na + 2HCl → 2NaCl + H₂

Number of moles of sodium:

Number of moles of sodium = mass / molar mass

Number of moles of sodium = 0.230 g / 23 g/mol

Number of moles of sodium = 0.01 mol

Enthalpy of reaction:

ΔHrxn = 2390 J / 0.01 mol

ΔHrxn = 239000 j/mol

ΔHrxn = 239 kj/mol

3 0

3 years ago

Given that the formula for mass percent is mass % = mass solutemass solution100%, what will be our starting assumption when conv

attashe74 [19]

Answer:

1. The starting assumption is an amount of 100 grams of solution.

2. It simplifies the problem, because the percentage tells directly the mass of solute present in 100 grams of solution and from that point the calculations are easy to do.

Explanation:

Percentages are always based on the amount of total substance, total solution if it is the case.

If it is mass percentage the amount of total substance is mass.

For instance, a 30% mass solution of sodium chloride means 30 grams of sodium chloride (solute) in 100 grams of solution (includes the solvent plus the solute).

mass percent is mass % = (mass solute / mass solution) × 100%,

Molarity is number of moles of solute per volume in liters of solution:

Molarity = (moles solute / liters solution)

In this case, to convert from percentage to molarity you start assuming a base of 100 grams of solution. For the example of the 30% sodium chloride solution, by assuming 100 grams of solution, you had 30 grams of solute, which you can convert into moles, and, by using the density of the solution (which you need to know), you convert the 100 grams of solution into volume (in liters). Then, you can divide the number of moles of solute into the number of liters of solution, having started with the assumption of 100 grams of solution.

Molality is the number of moles of solute per kilograms of solvent.

Molality = moles solute / kg of solvent.

Again, to convert from percentage to molality, your first step is to assume a base of 100 grams of solution. Then, for the same example of 30% sodium chloride, convert 30 grams of solute to moles, and the 100 grams of solution into 70 grams of solvent (100g solution - 30 grams solute = 70 grams solvent), which is 0.070 kg. Finally, divide the moles of solute by 0.070 kg of solvent.

Then, assuming the amount of solution equal to 100 grams simplifies the problem because the percentage tells directly the amount of solute, which you can convert into moles making calculations easier than with other amount of solution.

5 0

3 years ago