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lozanna [386]
4 years ago
10

What is the magnitude of the force of gravity between to 1000 kg cars which are separated by distance of 25. 0 km on an intersta

te highway? The force between the two cars will be what
Chemistry
1 answer:
kipiarov [429]4 years ago
3 0

Answer:

=1.068 ×10⁻¹³N

Explanation:

Force of gravity =Gm₁m₁/d² where G is the universal gravitation constant =G = 6.673 x 10-11 N m²/kg², m₁ and m₂ is the mass of object 1 and 2 respectively and d is the distance between them. First we change the distance into SI units i.e meters 25 km= 25000 m

F= (6.673 x 10⁻¹¹ N m²/kg²×1000 kg×1000 kg)/ (25000 m)²

=1.068 ×10⁻¹³N

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Consider a piece of gold jewelry that weighs 9.85 g and has a volume of 0.675 cm3 . The jewelry contains only gold and silver, w
AlekseyPX

Answer:

61.5096 %

Explanation:

Let the amount of gold in the jewelry = x g

Let the amount of silver in the jewelry = y g

Total mass of jewelry = 9.85 g

So,

x + y = 9.85 g    .................................1

Density = Mass / Volume

Given that:

Density of gold = 19.3 g/cm³

Thus, volume is:

Volume = Mass / Density = x / 19..3 cm³

Given that:

Density of silver = 10.5 g/cm³

Thus, volume is:

Volume = Mass / Density = y / 10.5 cm³

The total volume of the jewelry = 0.675 cm³

So,

\frac {x}{19.3}+\frac {y}{10.5}=0.675

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10.5 x + 19.3 y = 136.78875  ................2

Solving 1 and 2, we get that:

<u>x = 6.0587 g</u>

<u>y = 3.7913 g</u>

So, mass % of gold:

<u>Mass % = (6.0587 / 9.85)×100 = 61.5096 %</u>

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