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2 years ago

Which general equation shows a Single-displacement reaction?

1 answer:

6 0

Hello! The answer is D

A good note for these is when there are three elements, one being a singular element and another a compound and there’s a single switch, this could show a single-displacement

Have a good day gamer.

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Purpose Question:

SVETLANKA909090 [29]

Answer:

I will take Aspirin if I had a headache

3 0

3 years ago

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Unknown halogen X2 was added to each of two test tubes which contained aqueous NaCl and aqueous NaI, respectively. When hexane w

weeeeeb [17]

Answer:

$Br_2$

Explanation:

The compound $X_2$ is $Br_2$ .

The reaction included are:

$Br_2+NaCl--> No\ reaction$ (because bromine is less reactive than chlorine)

But , because of hexane the solution get dilute and its color changes to orange.

Now, NaI is added and we know Br is more reactive than I.

Therefore it replace it.

Reaction: $Br_2+NaI-->NaBr+I_2$

Purple color develop due to formation of Iodine.

7 0

3 years ago

Calculate the energy for vacancy formation in silver, given that the equilibrium number of vacancies at 800˚C (1073 K) is 3.6 ×

krek1111 [17]

Answer : The energy for vacancy formation in silver is, $1.762\times 10^{-19}J$

Explanation :

Formula used :

$N_v=N\times e^{(\frac{-E}{K\times T})}$

or,

$N=\frac{N_A\times \rho}{M}$

So,

$N_v=[\frac{N_A\times \rho}{M}]\times e^{(\frac{-E}{K\times T})}$

where,

$N_v$ = equilibrium number of vacancies = $3.6\times 10^{23}m^{-3}=3.6\times 10^{20}L^{-1}$

E = energy = ?

M = atomic weight = 107.9 g/mole

$N_A$ = Avogadro's number = $6.022\times 10^{23}mol^{-1}$

$\rho$ = density = $9.5g/cm^3=9.5g/ml=9500g/L$

T = temperature = $800^oC=273+800=1073K$

K = Boltzmann constant = $1.38\times 10^{-23}J/K$

Now put all the given values in the above formula, we get:

$3.6\times 10^{20}L^{-1}=[\frac{(6.022\times 10^{23}mol^{-1})\times 9500g/L}{107.9g/mol}]\times e^{[\frac{-E}{(1.38\times 10^{-23}J/K)\times 1073K}]}$

$E=1.762\times 10^{-19}J$

Therefore, the energy for vacancy formation in silver is, $1.762\times 10^{-19}J$

4 0

3 years ago

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When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. if 100 g of nitrogen react with 6 g of hydrogen,

vampirchik [111]

N2 + 3H2 --> 2NH3
When 100g of N2 , no of moles of N2= 100/(28)=3.57 mol
no. of moles of h2 = 6/(2)=3mol
Therefore h2 is limiting reagent.
no. of moles of ammonia= 3/3*2=2moles
mass of ammonia produced= 2 mol * (14+3)= 34g

4 0

3 years ago

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What is the name of the compound BrF

Rashid [163]

Bromine

hope that helps :)

7 0

3 years ago

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