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goldfiish [28.3K]
3 years ago
6

If 8.753 g of the heptahydrate produces 8.192 g of the hexahydrate, how many grams of anhydrous nickel(ii) sulfate could be obta

ined?
Chemistry
1 answer:
Ede4ka [16]3 years ago
5 0

Answer is: 4.826 grams of anhydrous nickel(II) sulfate could be obtained.

m(NiSO₄×7H₂O) = 8.753 g; mass of heptahydrate.

m(NiSO₄×6H₂O) = 8.192 g; mass of hexahydrate.

m(H₂O) = m(NiSO₄×7H₂O) - m(NiSO₄×6H₂O).

m(H₂O) = 8.753 g - 8.192 g.

m(H₂O) = 0.561 g.

m(NiSO₄) = m(NiSO₄×7H₂O) - 7 · m(H₂O).

m(NiSO₄) = 8.753 g - 7 · 0.561 g.

m(NiSO₄) = 4.826 g.

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The concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 M dextrose solution to 25 ml using a 25 ml volumetric flask is 0.56M.

Concentration is defined as the number of moles of a solute present in the specific volume of a solution.

According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

Where, M₁=1.0M, V₁=14ml, M₂=?, V₂=25ml

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M₂=(M₁V₁/V₂)

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M₂=(1.0M×14 ml/25 ml)

M₂=14 M/25

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6 0
1 year ago
Calculate the mass (in grams) of 8.56 moles of sulfur.
oksano4ka [1.4K]

Answer:

275g

Explanation:

Depending on the molar mass you are given, you can use that to solve this.

(I'm going based on my science class' molar mass of sulphur being 32.07g/mol)

Starting off, the formula for finding moles is

n=m/M (moles = mass / molar mass)

We can manipulate this equation to solve for mass.

m=Mn

now fill in what we now.

m = 32.07*8.56

mass = 274.5192

Now round for significant digits (if you are needed to do)

mass = 275g

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