Question

Sayid made a chart listing data of two colliding objects.

Answer 1

Answer:

velocity of combined objects is 6 m/s

Explanation:

As per law of conservation of momentum

total momentum before collision = total momentum after collision

since the two objects sticks together after collision so we will have

$m_1v_{1i} + m_2v_{2i} = (m_1 + m_2) v$

Now plug in all values in it

$300(10) + 100(-6) = (300 + 100) v$

$3000 - 600 = 400(v)$

$2400 = 400 v$

$v = 6 m/s$

so the missing value in the table is velocity which is 6 m/s