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alexdok [17]
3 years ago
7

Electromagnetic waves travel through space at a speed of _____.

Physics
2 answers:
Veseljchak [2.6K]3 years ago
6 0
The answer is C 300,000 kilometers per second

pogonyaev3 years ago
5 0

Ans: C) 300,000 kilometers per second

Electromagnetic waves are created by the movement of charges. This results in the generation of electric and magnetic fields which oscillate in a direction perpendicular to each other.

Electromagnetic waves carry a certain wavelength, frequency and speed. The speed of such waves as they travel through space is equal to the speed of light (c) = 3*10⁸ m/s

since 1 km = 10³ m

speed, c = 1 km * 3*10⁸ ms-1/10³ m

                = 300, 000 km/s

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7 0
3 years ago
A 10.0 cm object is 5.0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and th
fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
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\frac{1}{d_i}= -\frac{7}{60 cm}
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6 0
3 years ago
Read 2 more answers
Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity of +4.0 m/s a
DedPeter [7]

Answer:

As collision is elastic,thus we can use conservation of momentum equation

mA=0.2 kg

(vB)1=0 m/s.......................as it is on rest before collision

(vA)1=4 m/s

(vA)2=-1 m/s

(vB)2=2 m/s

using equation

(mA*vA+mB*vB)1= (mA*vA+mB*vB)2

Where 1 and 2 represents before and after collision

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6 0
3 years ago
A car moves at a constant speed of 90km/h from a starting point. Another car moves at 70km/h after 2hours from the same starting
emmainna [20.7K]

Answer:

400

Explanation:

5 0
2 years ago
The frequency of a wave is 200 Hz. The wavelength is 0.1 m. What is the period of the wave?
Aleks04 [339]
The formula for the period of wave is: wave period is equals to 1 over the frequency.waveperiod=\frac{1}{frequency}
To get the value of period of wave you need to divide 1 by 200 Hz. However, beforehand, you have to convert 200 Hz to cycles per second. So that would be, 200 cyles per second or 200/s.
By then, you can start the computation by dividing 1 by 200/s. Since 200/s is in fractional form, you have to find its reciprocal form and multiply it to one which would give you 1 (one) second over 200. This would then lead us to the value 0.005 seconds as the wave period.

wave period= 1/200 Hz
Convert Hz to cycles per second first
200 Hz x 1/s= 200/second
Make 200/second as your divisor, so:

wave period= 1/ 200/s

get the reciprocal form of 200/s which is s/200

then you can start the actual computation:

wave period= 1 x s divided by 200

this would give us an answer of 0.005 s. 
6 0
3 years ago
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