X² - 15 x + 36 = 0
x² - 12x - 3x + 36 = 0
x( x - 12) - 3( x - 12) = 0
(x - 3)( x - 12) = 0

x - 3 = 0
x = 3
or
x - 12 = 0
x = 12

The solutions are 3 and 12

7 0

3 years ago

If there are four teams in a league, how many games will have to be played so that each team plays every other team once?

Sedaia [141]

Answer:

6 matches

Step-by-step explanation:

Let’s call the teams A B C D

A will play B C D = 3 matches

B will play only C and D as it already played A, making 2 matches

C will play D, making 1 match

D has already played all

Total number of matches is thus 3 + 2 + 1 = 6 matches

3 0

4 years ago

I do not understand this. (-3 3/7) + 1/2

Anestetic [448]

Answer:

-3 6/14 + 7/14=

-2 20/14. + 7/14

- 2 13/14

7 0

4 years ago

Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent and invested $10,000 for one year at an annual

irinina [24]

Answer:

Total interest =$1296

Step-by-step explanation:

Kevin invested $8,000 for one year at a simple annual interest rate of 6 percent

Simple interest = $\frac{Pnr}{100}$

P=8000, n=1 year and r=6

interest = $\frac{8000(1)(6)}{100}$

Interest = 480 dollars

$compound \ interest =P(1+\frac{r}{n} )^{nt}-p$

P= 10000, t=1, r=8%=0.08, n=2 for semiannually

$compound \ interest =10000(1+\frac{0.08}{2} )^{2(1)}-10000$

Interest = 10816- 10000=816

Total interest = $480+816=1296$

5 0

4 years ago