Answer:
99.225
Step-by-step explanation:
10×3.15 is 31.5
31.5 squared is 99.225
Hope this helps!
Answer:
Step-by-step explanation:
Since 34 Lbs of seed is needed for 5 Acre's, You will need two find 1/5th of 34.
1/5 in decimal form is 0.2
34*0.2= 6.8
In order to cover 1 Acre of land you will need 6.8 lbs of seed.
Hope this helps!
Answer:
The person who receives the most will get $24
Step-by-step explanation:
Let
x ----> amount received by the first person
y ----> amount received by the second person
z ----> amount received by the third person
we know that
----> equation A
so
----> equation B
----> equation C
substitute equation B and equation C in equation A
solve for y
Find the value of x
Find the value of z
therefore
The person who receives the most will get $24
The answer is -8
====================================================
Explanation:
There are two ways to get this answer
Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8
-----------------------
The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4
g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8
Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8
Regardless of which method you use, the answer is -8
If a graph fails the vertical line test it's not a function; you can't have a single x map to two ys.
Vice versa, if the graph passes the verticle line test, it's a function.
The horizontal line test tests for injectivity aka one-to-one-ness; it has no bearing on whether something's a function.
