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2 years ago

The energy an object has by virtue of its position is kinetic energy. True False

Physics

1 answer:

nydimaria [60]2 years ago

8 0

Answer:

false

Explanation:

the energy an object has by virtue of its position is gravitational energy.

the energy which an object possess due to its motion is kinetic energy.

hope it helps !

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a 1210 kg roller coaster car is moving 6.33 m/s. as it approaches the station, brakes slow it down to 2.38 m/s over a distance o

Stels [109]

Answer:

4960 N

Explanation:

First, find the acceleration.

Given:

v₀ = 6.33 m/s

v = 2.38 m/s

Δx = 4.20 m

Find: a

v² = v₀² + 2aΔx

(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)

a = -4.10 m/s²

Next, find the force.

F = ma

F = (1210 kg) (-4.10 m/s²)

F = -4960 N

The magnitude of the force is 4960 N.

4 0

2 years ago

Read 2 more answers

A particle, of mass 6 kg, is in equilibrium on a rough horizontal plane under a force o-f magnitude T N, which acts at an angle

Helga [31]

Answer:

T is less than or equal to 19 N

Explanation:

3 0

2 years ago

A dog is walking back home and its motion is modeled by the graph above. What position was the dog at 3 seconds after it started

hammer [34]

6 meters because 6/3 = 10/5

4 0

2 years ago

What is the difference between organic and inorganic material?

babymother [125]

Organic materials comes from living things while inorganic materials comes from non living things

Organic materials are those composed mainly of carbon they are derived from living things while inorganic materials are derived from non living things sucjh as rocks etc

5 0

2 years ago

A delivery truck travels with a constant velocity up an 8 slope. A 60 kg box sits on the floor of the truck and, because of sta

Blababa [14]

Explanation:

Given that,

The slope of the ramp, $\theta=8^{\circ}$

Mass of the box, m = 60 kg

(a) Distance covered by the truck up the slope, d = 300 m

Initially the truck moves with a constant velocity. We know that the net work done on the box is equal to 0 as per work energy theorem as :

$W=\dfrac{1}{2}m(v^2-u^2)=0$

u and v are the initial and the final velocity of the truck

(b) The work done on the box by the force of gravity is given by :

$W=Fd\ cos\theta$

Here, $\theta=90+8=98^{\circ}$

$W=mgd\ cos\theta$

$W=60\times 9.8\times 300\ cos(98)$

W = -24550.13 J

(c) What is the work done on the box by the normal force is equal to 0 as the angle between the force and the displacement is 90 degrees.

(d) The work done by friction is given by :

$W_f=-W$

$W_f=24550.13\ J$

Hence, this is the required solution.

6 0

3 years ago