What r the answer choices? I'm
1 volt = 1 joule per coulomb.
Current doesn't actually pass 'through' a battery.
But if it did, then each coulomb would gain or lose 6 joules in traversing 6 volts, depending on its sign, and whether it climbed or fell.
The distance starting from the point to the lighthouse would be regarded as the hypotenuse.
And also will be the radius of the circle the beam of light is generating at that point.
So get the radius first
r = sqrt (1^2 + 5^2)
r = 5.099 km
find the circumference:
C = 2*pi * 5.099 km
C = 2 * 16.01898094
C = 32.04 km
Then find the speed in km/sec
One revolution: 60/2 = 30 sec per revolution
Speed = 32.04 km/30 sec
S = 1.068 km/sec is the speed of light
