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bogdanovich [222]
3 years ago
8

4. This is a

Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

Step-by-step explanation:

4). This is an exponential function.

5). Let the equation of this function is,

    f(x) = a(b)ˣ

    Since, two points (-1, 4) and (0, 6) are lying on the graph of the function,

    For (-1, 4),

    4 = a(b)⁻¹

    4 = \frac{a}{b} --------(1)

    For (0, 6),

    6 = a(b)⁰

    a = 6

    From equation (1),

    4 = \frac{6}{b}

    b = \frac{6}{4} = 1.5

    Therefore, equation of the function will be,

    f(x) = 6(1.5)ˣ

6). Now the value of f(-4) will be,

    f(-4) = 6(1.5)⁻⁴

           = 1.185

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Hope this helps!

Step-by-step explanation:

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F(x)=x-1/x^2-x-6 which is the graph of
hoa [83]

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The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

f\left(x\right)=x-\frac{1}{x^2}-x-6

x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:

\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0

-\frac{1}{x^2}-6=0

-1-6x^2=0

\mathrm{No\:Solution\:for}\:x\in \mathbb{R}

\mathrm{No\:x-axis\:interception\:points}

y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:

y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}

\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}

\mathrm{No\:y-axis\:interception\:point}

\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6

\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)

The graph is attached below.

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3 years ago
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