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xz_007 [3.2K]
2 years ago
10

Find the slope of the line that passes trough(5,-10) and (5,-4)

Mathematics
2 answers:
Gwar [14]2 years ago
3 0

Answer:

Answer Undefined

Step-by-step explanation:

This line is a vertical line because the x coordinate is the same on both points (5 is the x coordinate in both points). Vertical line's slopes are undefined because they go from up to down.

omeli [17]2 years ago
3 0

Answer:

Undefined

Step-by-step explanation:

Use the equation to find slope y2-y1/x2-x1

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3, -3

Step-by-step explanation:

an integer is a whole number

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The answer to your question is y=-5
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(x-3)(x+2)=0

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2 years ago
Unit activity: exponential and logarithmic functions
nirvana33 [79]

We will conclude that:

  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

y > 0.

For the logarithmic function we have:

g(x) = A*ln(x).

As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>
  • The domain of the exponential function is equal to the range of the logarithmic function.
  • The domain of the logarithmic function is equal to the range of the exponential function.

If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

3 0
1 year ago
Give an example of a polynomial that has the asymptotes of x=5 and y=0.5
BaLLatris [955]
(x²+4x+3)/2(x²-10x+25)

the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5

the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5 

this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)]  for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
5 0
3 years ago
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