Answer:
K = 0.0003 s⁻¹
Explanation:
The reaction is
2N₂O₅ = 4NO₂ + O₂
The equilibrium is
![K[N_{2} O_{5} ]=-\frac{1}{2} \frac{d[N_{2} O_{5} ]}{dt} \\\int\limits^y_x {d[N_{2} O_{5} ]}{} \, =-2k\int\limits^t_0 {dt} \,\\ln[N_{2} O_{5} ]=-2kt+ln[N_{2} O_{5} ]](https://tex.z-dn.net/?f=K%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7Bdt%7D%20%5C%5C%5Cint%5Climits%5Ey_x%20%7Bd%5BN_%7B2%7D%20O_%7B5%7D%20%5D%7D%7B%7D%20%5C%2C%20%3D-2k%5Cint%5Climits%5Et_0%20%7Bdt%7D%20%5C%2C%5C%5Cln%5BN_%7B2%7D%20O_%7B5%7D%20%5D%3D-2kt%2Bln%5BN_%7B2%7D%20O_%7B5%7D%20%5D)
a plot is attached
From the plot, the slope is -0.0006
-2 * K = -0.0006
K = 0.0003 s⁻¹
Answer:
6 HCl to 2 VOCl3
Explanation:
The coeffcients in front of the elements, represent moles. Therefore because the equation is balanced, you would evaluate your answer of the mole based off of what the question is asking. The question asked about the mole ratio of the two elements HCl to VOCL3. There is a number 6 in front of HCl which means that there are 6 moles of HCl, and there is a 2 in front of VOCL3 which means that there are 2 moles of VOCL3.
Therefore the correct answer will be 6 HCl to 2 VOCL3
The molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol, Option D is the correct answer.
<h3>What is enthalpy of Combustion ?</h3>
The energy released when a fuel is oxidized by an oxidizing agent is called enthalpy of Combustion.
It is given that
a 1.0 g sample of magnesium is burned to form MgO. in doing so, 25.5 kj of energy are released.
Molecular weight of Magnesium = 24.35g
24.35 g makes 1 mole of Mg
1g = 1/24.35
For 0.04 moles 25.5 kJ is released
for 1 mole 25.5 *1/.04
= 620 kj/mol
Therefore the molar enthalpy of combustion in kj/mol of magnesium is 620 kj/mol.
To know more about enthalpy of combustion
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<h3>
Answer:</h3>
3.3 × 10²³ atoms Cu
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 0.54 moles Cu
[Solve] atoms Cu
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
3.25188 × 10²³ atoms Cu ≈ 3.3 × 10²³ atoms Cu
Answer:
a
Explanation:
magma is lava and lava is magma