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3 years ago

Reactions eventually stop. What is generally the reason for this?

Chemistry

1 answer:

Rina8888 [55]3 years ago

4 0

Reactions eventually stop. Generally the reason for this :

C. One or more of the reactants has been used up.

Explanation:

A reaction is an action taken in response to something. If you're telling your parents that you want to move out, you'll see by their reaction that they're sad about it. A reaction is often a physical in nature.
A chemical reaction describes the way a chemical behaves when combined with another substance.
Reactants are substances initially present in a chemical reaction that are consumed during the reaction to make products. Some chemical reactions go to completion, resulting in all of the reactants becoming products. These reactions are said to be irreversible.
All chemical reactions involve both reactants and products. Reactants are substances that start a chemical reaction, and products are substances that are produced in the reaction
For example, burning methane in oxygen is irreversible.
In a chemical reaction, reactants that are not used up when the reaction is finished are called excess reagents.

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Answer:

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3 years ago

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The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s

raketka [301]

Answer : The equilibrium concentration of $H_3O^+$ in the solution is, $2.1\times 10^{-3}M$

Explanation :

The dissociation of acid reaction is:

$C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-$

Initial conc. c 0 0

At eqm. c-x x x

Given:

c = $7.0\times 10^{-2}M$

$K_a=6.3\times 10^{-5}$

The expression of dissociation constant of acid is:

$K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}$

$K_a=\frac{(x)\times (x)}{(c-x)}$

Now put all the given values in this expression, we get:

$6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}$

$x=2.1\times 10^{-3}M$

Thus, the equilibrium concentration of $H_3O^+$ in the solution is, $2.1\times 10^{-3}M$

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3 years ago

A) 30.22 g NaCl x 1 mol NaC l = 58.4430 Molar mass (g) NaCl=0.5171 mol NaCl

jekas [21]

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3 years ago

How many grams of methane gas (CH4) need to be combusted to produce 12.5 L water vapor at 301 K and 1.1 atm? Show all of the wor

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Answer is: 4.45 grams of methane gas need to be combusted.
Balanced chemical reaction: CH₄ + 2O₂ → CO₂ + 2H₂O.
Ideal gas law: p·V = n·R·T.
p = 1.1 atm.
T = 301 K.
V(H₂O) = 12.5 L.
R = 0,08206 L·atm/mol·K.
n(H₂O) = 1.1 atm · 12.5 L ÷ 0,08206 L·atm/mol·K · 301 K.
n(H₂O) = 0.556 mol.
From chemical reaction: n(H₂O) : n(CH₄) = 2 : 1.
n(CH₄) = 0.556 mol ÷ 2 = 0.278 mol.
m(CH₄) = 0.278 mol · 16 g/mol.
m(CH₄) = 4.448 g.

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3 years ago

What is the net charge of C

sashaice [31]

Explanation:

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2 years ago

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