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NemiM [27]
4 years ago
15

You dissolve the sample of fd&c red 40 (molar mass 496.4200 g/mol) in enough water to make 250.0 ml of solution. we call thi

s the stock solution. what is the concentration of the stock solution in terms of molarity?
Chemistry
1 answer:
icang [17]4 years ago
8 0
Molar mass 496.4200 g/mol

Number of moles:

40 g x 1 mol / 496.4200 => 0.08057 moles

Volume in liters:

250.0 mL / 1000 => 0.25 L

Therefore:

M = moles / V

M = 0.08057 / 0.25

 = 0.32228 M

hope this helps!
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3 years ago
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3 years ago
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Answer : The molar concentration of sucrose in the tea is, 0.0549 M

Explanation : Given,

Mass of sucrose = 3.765 g

Volume of solution = 0.200 L

Molar mass of sucrose  = 342.3 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of sucrose}}{\text{Molar mass of sucrose}\times \text{Volume of solution (in L)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{3.765g}{342.3g/mole\times 0.200L}=0.0549mole/L=0.0549M

Therefore, the molar concentration of sucrose in the tea is, 0.0549 M

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3 years ago
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