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3 years ago

Which statement about the relationship between mass in air and altitude is accurate?

Physics

1 answer:

3241004551 [841]3 years ago

3 0

Answer:

A) Mass in air is unrelated to altitude

Explanation:

Mass is the amount of matter contained in a substance. Altitude is the height of a body above a reference plane.

Mass and altitude are unrelated.

The mass of given body is the same everywhere in the universe provided no loss or gain of matter.
Altitude increases as distance from the reference widens.
Most often times, as altitude increases, temperature reduces due to the nature of the troposphere.

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A car stops with an acceleration of -20 m/s/s in 8 seconds. How far did it go while stopping?

Sophie [7]

Answer:

640 m.

Explanation:

The following data were obtained from the question:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Distance (s) =.?

Next, we shall determine the initial velocity (u) of the car. This can be obtained as follow:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u)

a = (v – u) / t

–20 = (0 – u) / 8

–20 = – u / 8

Cross multiply

–20 × 8 = – u

– 160 = – u

Divide both side by – 1

u = – 160 / – 1

u = 160 m/s

Finally, we shall determine the distance travelled by the car before stopping as follow:

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 160 m/s

Distance (s) =.?

s = (v + u)t /2

s = (0 + 160) × 8 /2

s = (160 × 8) /2

s = 1280 / 2

s = 640 m

Therefore, the car travelled 640 m before stopping.

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4 years ago

How much energy is transferred to 1.327 grams of water when the

never [62]

Answer: option B is correct

Explanation:

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3 years ago

Answer all 3 parts of this essay question: A) (5pts) If you have a Periodic Table that is NOT color coded, describe where to loo

cestrela7 [59]

Answer:

A) If you look at the vertical rows you can tell how many electrons there are on the outer shell eg. Group 7 (eg. nitrogen) has 7 electrons on its outer shell

B) They are in the same group

C) Helium,Argon and Organessom are all Nobel gasses

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4 years ago

A friend rides, in turn, the rims of three fast merry-go-rounds while holding a sound source that emits isotropically at a certa

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Complete Question

The complete question is shown on the first uploaded image

Answer:

The Ranking of the curve according to their speed would be equal Rank because $v_1 =v_2 =v_3$

The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

$w_1 >w_2 = w_3$

The ranking of the second third frequency would be the same but their ranking would be greater than that of the first frequency because

$r_2 =r_3 >r_1$

Explanation:

Mathematically Frequency can be represented as

$F = \frac{v}{\lambda}$

Where $\lambda$ is the wavelength and v is the velocity

Now looking at the diagram we see that

For the first frequency we have

Let the wavelength be $\lambda_1 = \lambda$ , and the frequency $F_1 = F$

For the second frequency

Let the wavelength be $\lambda_2 = 2 \lambda$ , and the frequency $F_2 = \frac{F}{2}$

For the third frequency

Let the wavelength be $\lambda_3 = 2\lambda$ , and the frequency $F_3 = \frac{F}{2}$

To obtain v for each of the frequency we make v the subject in the equation above for each frequency

So,

For the first frequency we have

$v_1 = \lambda_1 F_1 = \lambda F$

For the second frequency

$v_2 = \lambda_2 F_2 = 2 \lambda*\frac{F} {2} = \lambda F$

For the third frequency

$v_3 = \lambda_3 F_3 = 2 \lambda*\frac{F} {2} = \lambda F$

Hence

The Ranking of the curve according to their speed would be equal Rank because $v_1 =v_2 =v_3$

Mathematically angular speed can be represented as

$w = 2 \pi f$

For the first frequency we have

$w_1 = 2\pi F_1 = 2 \pi F$

For the second frequency

$w_2 = 2 \pi F_2 = 2 \pi \frac{F}{2} = \pi F$

For the third frequency

$w_3 = 2 \pi F_3 = 2 \pi \frac{F}{2} = \pi F$

Hence

The first frequency would have a higher rank compared to the other two which will have the same ranking when ranked with respect to their angular velocities because

$w_1 >w_2 = w_3$

Mathematically the relationship between the angular velocity and the linear velocity can be represented as

$v = wr$

=> $r = \frac{v}{w}$

Since the linear velocity is constant we have that

$r \ \alpha \ \frac{1}{w}$

This means that r varies inversely to the angular velocity ,What this means for ranking due to the radius is that the ranking of the second third frequency would be the same but their ranking would be greater than that of the first frequency because

$r_2 =r_3 >r_1$

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3 years ago

What is the value of work done on an object when a 70 newton force moves it 9.0 meters in the same direction as the force in jou

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Work done= 70 *9 = 63J

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4 years ago