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topjm [15]
3 years ago
15

PLEASE HELP ME PLEASE I NEED THE ANSWER QUICK

Chemistry
2 answers:
Alexeev081 [22]3 years ago
7 0
The answer is oxygen
kipiarov [429]3 years ago
4 0

Answer:

d

Explanation:

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What is the mass in grams of 3.05x10^25 gold atoms
Snezhnost [94]
9.96*10⁻²² is the answer, First you find the molar mass of gold, then you turn atoms to moles then moles to grams. There you go you're done!<span />
4 0
3 years ago
Are spiders scared of weed?
ki77a [65]

Answer:

yes the smoke from it scares them it also if, i remeber correctly, the smoke puts them to sleep

Explanation:

4 0
2 years ago
Read 2 more answers
A compound is made up of 80.0 % C and 20.0 % H. Its molar mass is 30.0 g. What is its molecular formula?
Greeley [361]

Answer:

Molecular formula = C₂H₆

Explanation:

Given data:

Percentage of hydrogen = 20.0 %

Percentage of carbon = 80.0 %

Molar mass = 30.0 g  

Empirical formula = ?

Solution:

Number of gram atoms of H = 20 / 1.01 = 19.8  

Number of gram atoms of C = 80 /12 = 6.7

Atomic ratio:

            C              :           H            

         6.7/6.7        :        19.8/6.7  

            1               :           3        

C : H = 1 : 3

Empirical formula is CH₃.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula = CH₃ = 12×1 +3×1.01 = 15.03 g/mol

n = 30 g/mol / 15.03 g/mol

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2 (CH₃)

Molecular formula = C₂H₆

8 0
2 years ago
Calculate the energy for the transition of an electron from the n = 2 level to the n = 5 level of a hydrogen atom.
katovenus [111]

The energy for the transition:

The energy for the transfer of an electron from the n=2 level to the n=5 level of a hydrogen atom is 4.57 x 10^{-19} J

Calculation:

We are aware of the energy levels as n=2 and n=5. So, we may determine the wavelength of the photon released by the electron during this transition using Rydberg's equation:

1/λ = R x (1/n^{2}_{final} - 1/n^{2} _{initial})

where,

1/λ = the wavelength of the emitted photon,

R = Rydberg's constant, 1.0974 x 10^{7} m^{-1}

n_{final} = the final energy level = 5

n_{initial} = the initial energy level = 2

Now, put the value in the above equation, we get,

1/λ = 1.0974 x 10^{7} m^{-1} x ( 1/5^{2} - 1/2^{2} )

1/λ = 1.0974 x 10^{7}m^{-1} x (-0.21)

1/λ = -0.23 x 10^{7}m^{-1}

λ = 4.347 x 10^{-7}m

Since, E = hc/λ

where,

h = Plank's constant = 6.626 x 10^{-34} Js

c = speed of light = 3 x 10^{8} m/s

So, the transition energy for your particular transition is,

E = 6.626 x 10^{-34} x 3 x 10^{8} / (4.347 x 10^{-7})

E = 4.57 x 10^{-19} J

Learn more about Rydberg's formula here,

brainly.com/question/13185515

#SPJ4

4 0
1 year ago
How many grams are in 4.28 x 10^2 atoms of Ca?
arlik [135]

2.85 grams

4.28x10^2 atoms (40.08 grams of Ca/ 6.02x10^23)

5 0
3 years ago
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