The given question is incomplete. The complete question is:
A chemist prepares a solution of barium chloride by measuring out 110 g of barium chloride into a 440 ml volumetric flask and filling the flask to the mark with water. Calculate the concentration in mole per liter of the chemist's barium chloride solution. Round your answer to 3 significant digits.
Answer: Concentration of the chemist's barium chloride solution is 1.20 mol/L
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in L
moles of
(solute) = 
Now put all the given values in the formula of molality, we get

Therefore, the molarity of solution is 1.20 mol/L
Answer:
-1, -2
Explanation:
West is left south is down east is right
potassium is just below the sodium in periodic table in s group !
so the valence electron of sodium and potassium is same and that is 1
Answer:
1x10⁻¹²
Explanation:
- Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)
At equilibrium:
The equilibrium constant for the the reaction can be written as:
[Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. <em>Cu₂S has no effect on the constant because it is a solid</em>.
Now we can <u>calculate the equilibrium constant</u>:
- Keq = (1.0x10⁻⁵)² * 1.0x10⁻² = 1x10⁻¹²
I know for number 4 the answer is c, sorry I can't help with the others.