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Anna71 [15]
3 years ago
8

Calculate the average rate of change for the graphed sequence from n = 2 to n = 4. (2 points)

Mathematics
2 answers:
gtnhenbr [62]3 years ago
6 0

Answer:

B.) −3.3125

Step-by-step explanation:

I am doing the test on flvs right now.

LUCKY_DIMON [66]3 years ago
3 0

Answer:

Average rate of chage = [change of y] / [change of x] = [- 10.125 - (-.35)] /[4 - 2] =

= -3.3125

Answer: option B.

Step-by-step explanation:

please mark as brillant

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What is the sum f 1.57 and 6.88
pentagon [3]
What is the sum of 1.57 and 6.88?

Ok, so lets work this out together!

Sum means add.

   6.88
+ 1.57

That would be: 

= 8.45

Hope i helped!
5 0
3 years ago
Read 2 more answers
Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-10, 12) and point (5, 3) rounded
Whitepunk [10]

Answer:

<h3>The answer is 17.5 units</h3>

Step-by-step explanation:

Using the distance formula

<h3>d =  \sqrt{ ({x2 - x1})^{2} +  ({y2 - y1})^{2}  }</h3>

the distance between (-10, 12) and (5, 3) is

<h3>d =  \sqrt{ ({5 + 10})^{2}  +  ({3 - 12})^{2} }</h3><h3>d =  \sqrt{ {15}^{2}  + ( { - 9})^{2} }</h3><h3>d =  \sqrt{225 + 81}</h3><h3>d =  \sqrt{306}</h3><h3>d = 3 \sqrt{34}</h3>

d = 17.492855

We have the final answer as

<h3>d = 17.5 units to the nearest tenth</h3>

Hope this helps you

4 0
3 years ago
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What is 4 √(2 × √(2 simplified?
larisa86 [58]

i think that it is 8

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3 years ago
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Solve for x<br><br><br><br><br> Thankyouhjg
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2 years ago
Maria finds a local gym that advertises 67 training sessions for $2052. Find the cost of 153 training sessions.
Ann [662]

Answer:

Cost\ of\ 153\ training\ sessions\ =\$4685.9\approx\$4686

Step-by-step explanation:

Cost\ of\ 67\ training\ sessions\ =\$2052\\\\Cost\ of\ 1\ training\ sessions\ =\frac{Total\ cost}{Total\ training\ sessions}\\\\Cost\ of\ 1\ training\ sessions\ =\frac{2052}{67}\\\\Cost\ of\ 153\ training\ sessions\ =153\times cost\ of\ 1\ training\ sessions\ \\\\Cost\ of\ 153\ training\ sessions\ =153\times\frac{2052}{67}=4685.9\\\\Cost\ of\ 153\ training\ sessions\ \$4685.9\approx4686

7 0
3 years ago
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