What is the fundamental cause of air circulation in earths atmosphere
1 answer:
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Answer:
386 m
Explanation:
Let's call the horizontal distance between the point of launch and the point of landing of the first package .
2 seconds after landing at , the plane has travelled a horizontal distance of
.
At this new point, the second package is launched. Because it is launched under the same conditions as the first, its horizontal distance from its point of launch is also .
To determine , we determine the time of fall of the package. Being a vertical motion, the drop has an initial velocity,
, of 0 m/s with acceleration,
, and a distance,
, of 160 m. We use the equation of motion:
In this time, the package, with a horizontal velocity of 50 m/s, travels the horizontal distance, , of
The distance apart between both packages is
Explanation:
Let the mass of two objects be m. Both objects move along the same line in opposite directions. Let v and u₂ are speeds of both objects before collision.
After the collision, both objects stick together and move with the speed of 0.1 V the direction of the velocity of the first mass before the collision.
Using the conservation of momentum as :
On solving above equation,
So, the speed of the second mass before the collision is 0.8 v. The negative sign shows that the it moves in opposite direction. Hence, this is the required solution.