Answer:
A. Electric potential energy into kinetic energy
Explanation:
The electric potential energy of the charged particles is converted into kinetic energy as the electron is released.
For this problem, we use the equations derived for rectilinear motion at constant acceleration. The equations are:
a = (v - v₀)/t
x = v₀t + 0.5at²
where
a is acceleration
v and v₀ are the final and initial velocities, respectively
x is the distance
t is the time
First, let's determine the a to be used in the second equation:
a = (7.5 m/s - 0 m/s)/1.7 s = 4.411 m/s²
x = (0)(1.7s) + 0.5(4.411 m/s²)(1.7 s)²
x = 6.375 m
Answer:
after t = 3 hours compound A remain 0.396 M
t = 12.98 hours
Explanation:
P = P_0*e^(-kt)
t = 30 minutes = 30/60 hours = 0.5 hours
and P_0 = 0.60M
and P after t = 0.5 hours is 0.56 M
(0.56/0.6) = e^(-kt)
0.933 =e^(-kt)
k = 0.138
P = P_0*e^(-0.138t)
Now after t = 3 hours,
P = 0.6* e^((-0.138)*3) = 0.396 M
time when P = 0.1 M
0.1 = 0.6*e^(-0.138t)
t = 12.98 hours
Answer:
ΔP = 20000 N s
Explanation:
To solve this problem we use the relation between momentum and moment
I = Δp
let's calculate the momentum
I = ∫F dt
if we use the average force
I = F t
I = 10000 2
I = 20000 N s
therefore with the first equation
ΔP = I = 20000 N s
(1) directed to the right
Explanation:
To the right of B, u(x) is a decreasing function & so its derivative is negative,this implies that the x component of the force on a particle at this position is positive,or that the force is directed towards right .Small deviations from equilibrium at point B causes a force to accelerate the particle away ,hence particle is in <u>unstable equilibrium.</u>
