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MrRissso [65]
3 years ago
5

Murphy loves pistachio nuts. Every Saturday morning, she walks to the market and buy some. Last week, she bought two pounds and

paid $7.96, and this week she bought only one half pound and paid $1.99, what's the constant rate of proportionality?
Mathematics
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

3.98

Step-by-step explanation:

From the above question,

Cost is directly proportional to the Number of pounds

Hence:

C ∝ N

= C = kN

Where k = Proportionality constant

We are told:

Last week, she bought two pounds and paid $7.96,

Hence:

7.96 = 2k

k = 7.96/2

k = 3.98

This week she bought only one half pound and paid $1.99,

1.99 = k × 1/2

k = 1.99/ 1/2

k = 3.98

Hence, the constant rate of proportionality is 3.98

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A middle-school art teacher, Ms. Velez, and her students are turning the school’s gymnasium into a student art museum for the da
boyakko [2]

Answer:19 to the 5th power

Step-by-step explanation:

U got to count all the zeros and that will be the number u put on top plus 19

3 0
3 years ago
5x + 4m = 43my + 6 solve for m
pav-90 [236]

9514 1404 393

Answer:

  m = (5x -6)/(43y -4)

Step-by-step explanation:

Subtract 4m+6 to separate m-terms from other terms.

  5x +4m -(4m +6) = 43my +6 -(4m +6)

  5x -6 = 43my -4m

  5x -6 = m(43y -4) . . . . factor out m

 (5x -6)/(43y -4) = m . . . . divide by the coefficient of m

7 0
2 years ago
Given functions f ( x ) = 1 √ x and m ( x ) = x 2 − 4 , state the domains of the following functions using interval notation.
babunello [35]

The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) =  1/√x

m(x) = x² - 4

Domain of f(x)/m(x):

f(x)/m(x) = (1/√x)/(x² - 4)

f(x)/m(x) = 1/√x(x² - 4)

The denominator cannot be zero:

√x(x² - 4) ≠ 0

x(x - 2)(x+2) ≠ 0

x ≠ 0, 2, -2

and x > 0

Domain of f(x)/m(x) is:   (0, ∞) - {0, 2, -2} or \:\left(0,\:2\right)\cup \left(2,\:\infty \:\right)

Domain of f(m(x)):

f(m(x)) = 1/√(x² - 4)

x² - 4 > 0

Domain: \rm \left(-\infty \:,\:-2\right)\cup \left(2,\:\infty \:\right)

Domain of m(f(x)):

= ((1/√x)² - 4)

Domain: \:\left(0,\:\infty \:\right)

Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.

Learn more about the function here:

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7 0
2 years ago
Solve for w (4w-5)(7-w)=0
nataly862011 [7]

Ask: When will (4w-5)(7-w) equal zero?

When 4w-5=0 or 7-w=0

Solve each of the 2 equations above

w = 5/4 , 7

7 0
3 years ago
at a party at the middle school over on third avenue next to the bank, $60\%$ of the students are seventh graders. these student
Vaselesa [24]

There are 600 students including the seventh and eighth graders at the party.

This problem uses the concept of percentages to define the conditions that are laid in front of us.

Let the original  number of students be S , and the number of seventh graders be   = 0.60S

We know that percent is used to convey the mathematical term of a fraction multiplied by 100.

Total students  after 20 eighth graders arrive = S + 20

And we have that

Number of seventh graders / total number of students  =  58%

.60S  / [ S + 20 ]  =   .58    we multiply both sides by  S +  20

0.60S  =0 .58 [ S + 20]

.60S  = .58S + 11.6   we subtract  0.58S from  both the sides

0.02S = 11.6  we divide both the sides  by .02

S  = 11/6 / 0.02 =    580

So the total number of students = 580 + 20  = 600 .

Hence there are 600 students at the party at that time.

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5 0
1 year ago
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