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Sedaia [141]
3 years ago
12

Pls help I have to submit it​

Physics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

Acceleration =

2 \: ms {}^{ - 2}

Explanation:

Acceleration =

\frac{change  \: in  \: velocity }{time}

=》

\frac{21 - 15}{3}

=》

\frac{6}{3}

=》

2

hence, acceleration =

2 \: ms {}^{ - 2}

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A sports car accelerates from 0 to 25 meters per second in 4 seconds. What is its acceleration?
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Answer:

6.25 ms²

Explanation:

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3 years ago
The earth has a vertical electric field at the surface, pointing down, that averages 119 N/C . This field is maintained by vario
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Answer:

q=5.37*10^{5}C

Explanation:

If we assume that the Earth is a spherical conductor, according to  Gauss's Law, the electric field is given by:

E=\frac{kq}{r^2}

Here k is the Coulomb constant, the excess charge on the Earth's surface and r its radius. Solving for q:

q=\frac{Er^2}{k}\\q=\frac{119\frac{N}{C}(6.371*10^6m)^2}{8.99\frac{N\cdot m^2}{C^2}}\\q=5.37*10^{5}C

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3 years ago
Consider a situation where a constant force of 25 N acts on an object having a mass of 2 kg for 3 seconds. What is the work done
blagie [28]

Answer:

Work done W =1406.25 J

Explanation:

Work done on a body can be calculated using newton's 2nd laws:

F=ma

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Hence acceleration of the block is given by:

\Rightarrow a=\frac{25}{2}=12.5m/s^2

Displacement of the object is given by:

\Rightarrow S=ut+\frac{1}{2}at^2

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\Rightarrow S=0*3+\frac{1}{2}(12.5)3^2

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3 years ago
A railroad freight car, mass 15,000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples w
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Answer:

The speed of the two cars after coupling is 0.46 m/s.

Explanation:

It is given that,

Mass of car 1, m₁ = 15,000 kg

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Initial speed of car 2, u₂ = 0

Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :

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3 0
3 years ago
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