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Sedaia [141]
3 years ago
12

Pls help I have to submit it​

Physics
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

Acceleration =

2 \: ms {}^{ - 2}

Explanation:

Acceleration =

\frac{change  \: in  \: velocity }{time}

=》

\frac{21 - 15}{3}

=》

\frac{6}{3}

=》

2

hence, acceleration =

2 \: ms {}^{ - 2}

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What is the current when the resistance is 5 ohms and the voltage is 10 volts?
Travka [436]
Ohm's Law states V = IR
So,
I = V/R
The answer is B. 10/5=2 amps
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3 years ago
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If you drop a ball off a cliff, it starts out a 0 m/s. After 1 s, it will be traveling at about 10 m/s. If air resistance is rem
Softa [21]

Answer: (C) The ball will accelerate to about 20 m/s.

Explanation: The ball is in free fall and no other but gravitational force acts on it. This means the ball will be subject to the gravitational acceleration, which is about 9.8 m/s^2. So after one additional second the ball will increase its velocity to (10+9.8) m/s = 19.8 m/s or approx. 20 m/s.

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A spherical shell has inner radius 1.5 m, outer radius 2.5 m, and mass 850 kg, distributed uniformly throughout the shell. What
Nimfa-mama [501]

Answer:

The magnitude of the gravitational force is 4.53 * 10 ^-7 N

Explanation:

Given that the magnitude of the gravitational force is F = GMm/r²

mass M = 850 kg

mass m = 2.0 kg

distance d = 1.0 m , r = 0.5 m

F = GMm/r²

Gravitational Constant G = 6.67 × 10^-11 Newtons kg-2 m2.

F = (6.67 × 10^-11 * 850 * 2)/0.5²

F = 0.00000045356 N

F = 4.53 * 10 ^-7 N

3 0
3 years ago
A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. C
lozanna [386]

Hello!

A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed.

We have the following data:

* velocity (in mph)

(V1) = 35.0 mph

(V2) = 40.0 mph

(V3) = 50.0 mph

* weights for the time (in hours)

(T1) = 1.00 hour

(T2) = 0.0500 hour

(T3) = 2.00 hours

We apply the data to the weighted average formula to find the average speed, let us see:

Weight\:Average = \dfrac{V_1*T_1+V_2*T_2+V_3*T_3}{T_1+T_2+T_3}

Weight\:Average = \dfrac{35.0*1.00+40.0*0.0500+50.0*2.00}{1.00+0.0500+2.00}

Weight\:Average = \dfrac{35+2+100}{3.05}

Weight\:Average = \dfrac{137}{3.05}

Weight\:Average = 44.91803279...

\boxed{\boxed{Weight\:Average = 44.92\:mph}}\Longleftarrow(Average\:Speed)\:\:\:\:\:\:\bf\purple{\checkmark}

Answer:

The Average Speed is approximately 44.92 mph

_______________________

\bf\purple{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7 N. What is the acceleration of the box?
Marysya12 [62]

Answer:

F=ma

a=F/m=9.7N/5.5Kg=1.8 m/s^2

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4 years ago
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