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3 years ago

How does momentum relate to impulse ?

Physics

1 answer:

fomenos3 years ago

5 0

Answer:

C. Impulse = F*t=(m*a)*t= m*(a*t) = m*Dv= D(Momentum) (“D” here’s mean Delta so change in)

Explanation:

In fact, the impulse is equal to the change in momentum of an object.

Impulse is defined as the product between the force (F) and the time (t):

$I=Ft$

however, the force is defined as the product between mass (m) and acceleration (a):

$F=ma\\I=(ma)t$

But the product a (acceleration) times t (time) is equal to the change in velocity of the object:

$I=m(at)=m \Delta v$

And this is exactly the definition of change in momentum:

$I = m\Delta v = \Delta p$

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In the equation for centripetal force, which expression represents the centripetal acceleration of the object? mv2 StartFraction

Sphinxa [80]

Answer: $\frac{V^{2}}{r}$

Explanation:

According to Newton's 2nd Law of motion the force $F$ is proportional to the mass $Fm$ and acceleration $a$ :

$F=m.a$ (1)

On the other hand, the equation for the Centripetal force is:

$F=\frac{mV^{2}}{r}$ (2)

Where:

$V$ is the velocity

$r$ is the radius of the circular motion

Making (1) and (2) equal:

$m.a=\frac{mV^{2}}{r}$ (3)

Hence:

$a=\frac{V^{2}}{r}$ This is the expression for the centripetal acceleration

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Monica [59]

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2 years ago

A certain car engine delivers enough force to create 630 N⋅m of torque when the engine is operating at 3200 revolutions per minu

jekas [21]

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Replacing,

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2 years ago

An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?

NeX [460]

Hey there!

We are given ,

Acceleration, a = -2m/s^2

Initial velocity , u = 15m/s

Time , t = 5 seconds

We know that ,
V=u+at

Now , final speed ,

V = 15+(-2)(5)

V = 15-10

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Hope this helps you dear :)
Have a good day <3

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1 year ago