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Archy [21]
2 years ago
14

An atom that undergoes radioactive decay and has a large nucleus most likely contains..

Chemistry
1 answer:
mojhsa [17]2 years ago
5 0
An atom that undergoes radioactive decay and has a large nucleus most likely contains....<span>- More protons than electrons.</span>
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A binding protein binds to a ligand L with a Kd of 400 nM. What is the concentration of ligand when Y is (a) 0.25, (b) 0.6, (c)
Mrac [35]

Answer:

(a) 133.33nm

(b) 600nm

(c) 7,600nm

Explanation:

The concentration of Y can be determined by using the formula:

Y = \dfrac{[L]}{k_d+[L]}

where;

[L] = concentration of the binding ligand.

kd = 400 nm

Thus:

When Y = 0.25; we get :

0.25 = \dfrac{[L]}{400+[L]}

0.25 (400 + [L]) = [L]

100 + 0.25[L] = [L]

100 = [L] - 0.25 [L]

100 = 0.75 [L]

[L] = 100/0.75

[L] = 133.33 nm

At, Y = 0.6

0.6 = \dfrac{[L]}{400+[L]}

0.6 (400 + [L]) = [L]

240 + 0.6[L] = [L]

240 = [L] - 0.6 [L]

240 = 0.4 [L]

[L] = 240/0.4

[L] = 600 nm

At, Y = 0.95

0.95 = \dfrac{[L]}{400+[L]}

0.95 (400 + [L]) = [L]

380 + 0.95[L] = [L]

380 = [L] - 0.95 [L]

380 = 0.05 [L]

[L] = 380/0.05

[L] = 7600 nm

4 0
3 years ago
Which is a single ringed nitrogeo base?<br><br> A)adenine<br> B)guanine<br> C)thymine<br> D)ribose
pogonyaev
A single ringed nitrogeo base is thymine (C)

3 0
3 years ago
ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!
sp2606 [1]

Answer:

The answer is A, if im not mistaken

8 0
3 years ago
Which of the following groups of elements are likely to be radioactive? (5 points) a Actinides b Noble gases c Transition metals
Nataly [62]

Answer:

Actinides

Explanation:

They are defined as "any of the series of fifteen metallic elements from actinium (atomic number 89) to lawrencium (atomic number 103) in the periodic table. They are all radioactive, the heavier members being extremely unstable and not of natural occurrence"

3 0
3 years ago
Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.
shepuryov [24]

We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").

The first two electrons contribute to bonding. The next two are anti-bonding.

The next six contribute to bonding, and the following six are anti-bonding.

So, if we start with CN+, which has 4+5-1 (8) valence electrons, we note that the first two electrons contribute to bonding, while the next two cancel this out; the next four contribute to bonding, so the bond order is 4/2 = 2.

If we add one more electron to get CN, there are now 5 bonding electrons, giving bond order 5/2=2.5.

Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)

Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:

CN+ < CN < CN-

Lewis structures will verify that CN- has a triple bond, but they do not work particularly well for CN+ and CN.

learn more about bond orders at

brainly.com/question/9713842

#SPJ1

3 0
1 year ago
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