According to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
What is exocytosis?
It is the expulsion, by cells, of particles that, due to their size, cannot pass through the cell membrane.
In this sense, it is the process by which different types of molecules contained in a cytoplasmic vesicle of a cell are secreted. Insulin is released to the outside by exocytosis, intervening in the process of glucose entry into cells.
Therefore, we can conclude that according to the research, the correct option is exocytosis. Insulin is made by pancreatic cells, packaged in small vesicles, and then released into the bloodstream. This describes <u>exocytosis</u> cell transport.
Learn more about exocytosis here: brainly.com/question/1193597
#SPJ1
Answer:
A
Explanation:
Liquid cooling is applied around the uranium rods to cool them. When this water is heated thanks to uranium, it produces water vapor.
<span>The
DNA is stored cold with the instagene matrix after boiling samples in order to
slow bacterial growth. In that way, you will greatly slow down the activity of
any remaining enzymes that could harm your DNA. Most likely it is a way of
preserving the DNA and to avoid it bacterial contamination.</span>
Answer:
The correct answer will be option-B
Explanation:
Meiosis is a way of cell division used by the organism to produce a large number of cells from a few parent cells. This is used to make the gametes of the body.
Meiosis produces four daughter cells from a single parent cell in two stages that is meiosis I and II. Each stage proceeds in four phases- prophase, metaphase, anaphase and telophase.
The reduction division of the chromosomes or the ploidy number takes place during anaphase I of meiosis I and not prophase I which is the initial phase of the division. Therefore, during prophase I the chromosome number of the cell remains the same.
Thus, Option-B is the correct answer.
Answer:
c = Enzymatic activity
e = Attachment to ECM and cytoskeleton
f = Signal reception and relay
g = Transport
h = Intercellular junctions
i = Cell-cell recognition
a = Phospholipid bilayer
b = Fibers of extracellular matrix (ECM)
d = Microfilaments of cytoskeletons
Explanation:
c) Enzymatic activity is an indication of the amount of active enzymes present to increase a reaction rate
e) Attachment to ECM and cytoskeleton is enabled by integrins that take signals from the ECM and control signaling pathways of the cell
f) Signal reception and relay is the transduction of signal
g) Transport is the movement of matter in and out of the cell through the cell membrane
h) Intercellular junctions are the contact regions between adjacent cells and plasma membrane
i) Cell-cell recognition is power of the cell to decipher the different neighboring cells in the cell's environment
a) Phospholipid bilayer consists of a hydrophobic interior and a hydrophilic exterior
b) Fibers of extracellular matrix (ECM) are ECM associated the cell
d) Microfilaments of cytoskeletons consist of actin and aid in cellular movement.
