What is the solution of the equation e^xe^2x = 4? Round your answer to the nearest hundredth.
1 answer:
The equation is:
[e^x] [e^(2x)] = 4
1) Applying property of multiplication of powers wiith same base =>
e ^ (x + 2x) = 4
=> e ^ (3x) = 4
2) Applying logarigth properties
3x = ln(4)
=> x = ln(4) / 3 ≈ 1.38629 / 3 ≈ 0.4621
Answer: x = ln(4) / 3 ≈ 0.4621
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