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777dan777 [17]
3 years ago
9

calculate the volume (in mL) of 0.100 M CaCl2 needed to produce 1.00 g of CaCO3 (s). There is an excess of Na2CO3. Volume of cal

cium chloride in mL
Chemistry
1 answer:
shepuryov [24]3 years ago
5 0

Answer:

100. mL

Explanation:

Step 1: Write the balanced equation for the double displacement reaction

CaCl₂ + Na₂CO₃ ⇒ 2 NaCl + CaCO₃

Step 2: Calculate the moles corresponding to 1.00 g of CaCO₃

The molar mass of CaCO₃ is 100.09 g/mol.

1.00 g × 1 mol/100.09 g = 0.0100 mol

Step 3: Calculate the moles of CaCl₂ required to produce 0.0100 moles of CaCO₃

The molar ratio of CaCl₂ to CaCO₃ is 1:1. The moles of CaCl₂ required are 1/1 × 0.0100 mol = 0.0100 mol.

Step 4: Calculate the volume of 0.100 M CaCl₂ that contains 0.0100 mol

0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L = 100. mL

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Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1
Korvikt [17]

The molecular mass of Carvone is calculated as;

                          =  12 (C)₁₀  +  1.008 (H)₁₄  +  16 (O)

                          =  120  +  14.112  +  16

                          =  150.112

%age of Carbon;

                          =  (120 ÷ 150.112) × 100

                          =  79.94 %

%age of Hydrogen;

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                          =  9.40 %

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7 0
3 years ago
A piece of fossilized wood has a carbon-14 radioactivity that is 1/4 that of new wood. the half-life of carbon-14 is 5730 years.
Marizza181 [45]

Answer:

1.146 x 10⁴ year.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

<em></em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = ??? years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]

(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.

∴ <em>t </em>= 1.386/ (1.21 x 10⁻⁴ year⁻¹) =  <em>1.146 x 10⁴ year.</em>

3 0
3 years ago
Will give 50 points, If a decrease in temperature accompanies a reaction, what occurred?
Ede4ka [16]

Answer:

A.

Explanation:

3 0
3 years ago
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