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jekas [21]
4 years ago
7

Does the law of conservation of mass apply to physical changes or just chemical changes?

Chemistry
1 answer:
slega [8]4 years ago
4 0
It applies to both physical and chemical changes.
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What is the carbon nucleophile which attacks molecular bromine in the acid-catalyzed α-bromination of a ketone?
Usimov [2.4K]

The enol carbon or ∝-carbon  nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone

Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid  is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.

learn more about ketone

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8 0
2 years ago
Is coal limited or unlimited give reasons
algol13

Answer:

Limited

Explanation:

Once it is used once, it is not reusable. Also, there's a possibility to use ALL the coal there is. That's why it's an unrenewable source, unlike the sun, wind, or water that never ends. Those are renewable

8 0
3 years ago
Read 2 more answers
What is a negatively charged ion
dem82 [27]

an electrically charged atom or group of atoms formed by the loss or gain of one or more electrons, as a cation (positive ion) , which is created by electron loss and is attracted to the cathode in electrolysis, or as an anion (negative ion) , which is created by an electron gain and is attracted to the anode.

7 0
3 years ago
16. ELECTRONS ALWAYS FILL THE LOWEST ENERGY LEVEL AVAILABLE FIRST
True [87]

Answer:

Electrons in the outermost energy level of an atom are called VALENCE ELECTRONS.

3 0
4 years ago
A 0.500 m solution of a weak base has a ph of 9.75. what is the base hydrolysis constant, kb, for the weak base?
Vladimir [108]
When we have PH = 9.75
So we can get POH = 14 - 9.75 = 4.25 
and when POH = - ㏒[OH-]
by substitution:
4.25 = -㏒[OH-]
∴[OH] = 5.6x10^-5
from this reaction equation:
BOH ↔ B+  + OH-
∴[OH-] = [B+]= 5.6x10^-5 M
and Equ [BOH] = 0.5 m - X
                          = 0.5 - (5.6x10^-5)
                          =  0.4999
∴ Kb = [OH-][B+]/[BOH]
         = (5.6x10^-5)^2 / 0.4999
         = 6.27x10^-9

8 0
3 years ago
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