Answer:
See the answer beloew, please.
Explanation:
The concepts of heat and temperature are related, but they are not the same. Temperature refers to a physical quantity which indicates the amount of heat. The latter corresponds to the energy that moves from one body to another, thus being able to raise or lower the temperature.
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The conversion factor between the unit in meter and that of kilometer is that, 1 kilometer = 1000m
For the given above,
(288 m³) x (1 km / 1000 m)³ = 2.88 x 10^-7
Thus, 288 m³ is also equal to 2.88 x 10^-7 km³.
Answer:
7.23 J
Explanation:
Step 1: Given data
- Mass of graphite (m): 566.0 mg
- Initial temperature: 5.2 °C
- Final temperature: 23.2 °C
- Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹
Step 2: Calculate the energy required (Q)
We will use the following expression.
Q = c × m × ΔT
Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)
Q = 7.23 J
