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stiks02 [169]
3 years ago
15

What's the optical illusion also known as?​

Physics
1 answer:
shepuryov [24]3 years ago
8 0

Answer:

An optical illusion (also called a visual illusion) is an illusion caused by the visual system and characterized by a visual percept that arguably appears to differ from reality. ... Cognitive visual illusions are the result of unconscious inferences and are perhaps those most widely known.

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How do I solve this problem please help
frosja888 [35]

Answer:

som,eythiung did cant wait

Explanation:

ya so i texted maria and she said i con c()me over so letyeyey yeah betty letty

PAINN I MISS JUOICE WORLDD PAINNNN

7 0
3 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
3 years ago
Read 2 more answers
In 1958, Meselson and Stahl conducted an experiment to determine which of the three proposed methods of DNA replication was corr
Korolek [52]

Answer:

Explanation:

The original has hybrid 15N/14N DNA, and the second generation has both hybrid 15N/14N DNA and 14N/14N DNA. No 15N/15N DNA was observed. In this experiment:  

Nitrogen is a significant component of DNA. 14N is the most bounteous isotope of nitrogen, however, DNA with the heavier yet non-radioactive and 15N isotope is likewise practical.  

E. coli was developed for several generations in a medium containing NH4Cl with 15N. When DNA is extracted from these cells and centrifuged on a salt density gradient, the DNA separates at which its density equals to the salt arrangement. The DNA of the cells developed in 15N medium had a higher density than cells developed in typical 14N medium. After that, E. coli cells with just 15N in their DNA were transferred to a 14N medium.

DNA was removed and compared to pure 14N DNA and 15N DNA. Immediately after only one replication, the DNA was found to have an intermediate density. Since conservative replication would result in equal measures of DNA of the higher and lower densities yet no DNA of an intermediate density, conservative replication was eliminated. Moreso, this result was consistent with both semi-conservative and dispersive replication. Semi conservative replication would result in double-stranded DNA with one strand of 15N DNA, and one of 14N DNA, while dispersive replication would result in double-stranded DNA with the two strands having mixtures of 15N and 14N DNA, either of which would have appeared as DNA of an intermediate density.  

The DNA from cells after two replications had been completed and found to comprise of equal measures of DNA with two different densities, one corresponding to the intermediate density of DNA of cells developed for just a single division in 14N medium, the other corresponding to DNA from cells developed completely in 14N medium. This was inconsistent with dispersive replication, which would have resulted in a single density, lower than the intermediate density of the one-generation cells, yet at the same time higher than cells become distinctly in 14N DNA medium, as the first 15N DNA would have been part evenly among all DNA strands. The result was steady with the semi-conservative replication hypothesis. The semi conservative hypothesis calculates that each molecule after replication will contain one old and one new strand. The dispersive model suggests that each strand of each new molecule will possess a mixture of old and new DNA.

8 0
4 years ago
How to determine the amount of resistance when two or more resistors are in parallel.
Elena L [17]

Answer: 1/R = 1/R1 + 1/R2+ ...+ 1/Rn

R is resistance of system in which there are resistors R1, R2 , ... Rn parallel.

3 0
3 years ago
Calculate the acceleration of a skier heading down a 10.0º slope, assuming the coefficient of friction for waxed wood on wet sno
lutik1710 [3]

(a) 0.74 m/s^2

Explanation:

There are two forces acting on the skier: the component of the weight parallel to the slope, which acts downward, and the frictional force, which acts upward along the incline.

The component of the weight parallel to the inclined plane is:

W= m g sin \theta

where m is the mass of the skier, g=9.81 m/s^2 and \theta=10^{\circ}.

The frictional force is instead

F_f = -\mu m g cos \theta

\mu=0.1 is the coefficient of friction for waxed wood on wet snow.

If we apply Newton's second law, we can write that the net force must be equal to the product of mass per acceleration:

mgsin \theta -\mu mg cos \theta =ma

And symplifying m, we can find the acceleration:

a=g sin \theta-\mu g cos \theta=

=(9.81 m/s^2)(sin 10^{\circ})-(0.1)(9.81 m/s^2)(cos 10^{\circ})=0.74 m/s^2


(b) 5.7^{\circ}

Explanation:

This time, the skier is moving at constant velocity. Therefore, the acceleration is zero (a=0) and Newton's second law becomes:

mg sin \theta - \mu m g cos \theta=0

By simplifying, we get

tan \theta = \mu

From which we can find the angle at which the skier could coast at a constant velocity:

\theta= tan^{-1} (\mu) = tan^{-1} (0.1)=5.7^{\circ}



6 0
3 years ago
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