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Ainat [17]
3 years ago
15

Michelle is having a poster printed from a picture that is 4 inches wide by 6 inches tall. The enlarged poster is 20 inches wide

and 30 inches tall. Which proportion can be used to represent the picture sizes
Mathematics
2 answers:
Taya2010 [7]3 years ago
6 0
Hello!
----------
A proportion that can be used to represent the picture sizes is p(poster printed) times 4 equals e(enlarged poster), or p*4=e.
----------
Have a great day!
Gennadij [26K]3 years ago
3 0

Answer with Step-by-step explanation:

Michelle is having a poster printed from a picture that is 4 inches wide by 6 inches tall.

The enlarged poster is 20 inches wide and 30 inches tall.

20=4×5

i.e. width of enlarged picture=5×width of actual picture

30=6×5

i.e. height of enlarged picture=5×height of actual picture

Hence, proportion that can be used to represent the picture sizes is:

picture:enlarged picture = 1:5

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\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

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\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

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\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

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\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

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\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

\rm \:  =  \: \dfrac{4}{24}

\rm \:  =  \: \dfrac{1}{6}

<u>Hence, </u>

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