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Ainat [17]
4 years ago
15

Michelle is having a poster printed from a picture that is 4 inches wide by 6 inches tall. The enlarged poster is 20 inches wide

and 30 inches tall. Which proportion can be used to represent the picture sizes
Mathematics
2 answers:
Taya2010 [7]4 years ago
6 0
Hello!
----------
A proportion that can be used to represent the picture sizes is p(poster printed) times 4 equals e(enlarged poster), or p*4=e.
----------
Have a great day!
Gennadij [26K]4 years ago
3 0

Answer with Step-by-step explanation:

Michelle is having a poster printed from a picture that is 4 inches wide by 6 inches tall.

The enlarged poster is 20 inches wide and 30 inches tall.

20=4×5

i.e. width of enlarged picture=5×width of actual picture

30=6×5

i.e. height of enlarged picture=5×height of actual picture

Hence, proportion that can be used to represent the picture sizes is:

picture:enlarged picture = 1:5

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Keith earns $45.00 in 2 hours. How much would he earn in 9 hours?
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Answer:

$202.50

Step-by-step explanation:

$45/2=22.5 (hourly rate)

22.5x9=202.50

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What is the x-value of the solution to this system of equations?
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Plug in for x.

7(2y - 4) + 5y = -66

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Put it back into the equation.
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What does 12 x 10 to the power of 6 equal to?
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A stock market analyst notices that in a certain year, the price of IBM stock increased on 131 out of 252 trading days. Can thes
san4es73 [151]

Answer:

95% confidence interval for the proportion of days that IBM stock increases.

(0.45814 , 0.58146)

Step-by-step explanation:

<u><em>Step:1</em></u>

Given that a stock market analyst notices that in a certain year, the price of IBM stock increased on 131 out of 252 trading days.

Given that the sample proportion

                      p^{-} = \frac{131}{252} = 0.5198

Level of significance = 0.05

Z₀.₀₅ = 1.96

<u><em>Step:2</em></u>

<u><em>95% confidence interval for the proportion of days that IBM stock increases.</em></u>

<u><em></em></u>(p^{-} - Z_{0.05} \frac{\sqrt{p(1-p)} }{\sqrt{n} } , p^{-} + Z_{0.05} \frac{\sqrt{p(1-p)} }{\sqrt{n} } )<u><em></em></u>

(0.5198 - 1.96(\sqrt{\frac{0.5198(1-0.5198)}{252} } , 0.5198 +1.96(\sqrt{\frac{0.5198(1-0.5198)}{252} })

(0.5198 -  0.06166 , 0.5198+0.06166)

(0.45814 , 0.58146)

<u><em>Final answer:-</em></u>

95% confidence interval for the proportion of days that IBM stock increases.

(0.45814 , 0.58146)

3 0
3 years ago
5/8,0.5,2/5,0.78 greatest to least
vitfil [10]
.78, 5/8, .5, 2/5 should be the correct answer. all you do is plug 5/8 into the calculator which is .625 and 2/5 is .4
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3 years ago
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