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3 years ago

There was 1 liter of water in the water bottle. Tom drank 200 milliliters of water. How many liters of water are left?

Mathematics

2 answers:

Lorico [155]3 years ago

8 0

Answer:

.8 L or 800 ML

Step-by-step explanation:

1000 ML in a L, 1000-200 = 800.

devlian [24]3 years ago

3 0

Answer:

.8L

Explanation:

Logic

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Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d), one of which is co

arlik [135]

A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

$P(C) = \frac{1}{4}$

The probability of choosing wrong answer is

$P(W) = \frac{3}{4}$

Using the multiplication rule
$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

$WWC$

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

$WCW$

Or the first one is correct and the last two are wrong. This will give the arrangement,

$CWW$
.

$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

$P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}$

$P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}$

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

$P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64} \\ \\ P(One \: Correct) = \frac{27}{64}$

7 0

3 years ago

Read 2 more answers

A certain type of automobile battery is known to last an average of 1140 days with a standard deviation of 80 days. If 400 of th

Sever21 [200]

Answer:

Mean = $\mu = 1140$

Standard deviation = $\sigma = 80$

Find the probabilities for the average length of life of the selected batteries.

A)The average is between 1128 and 1140.

We are supposed to fidn P(1128<x<1140)

Formula : $Z=\frac{x-\mu}{\sigma}$

At x = 1128

$Z=\frac{1128-1140}{80}$

$Z=-0.15$

Refer the z table for p value

P(x<1128)=0.4404

At x = 1140

$Z=\frac{1140-1140}{80}$

$Z=0$

Refer the z table for p value

P(x<1140)=0.5

So,P(1128<x<1140)=P(x<1140)-P(x<1128)=0.5-0.4404=0.0596

Hence the probabilities for the average length of life of the selected batteries is between 1128 and 1140 is 0.0596

B)The average is greater than 1152.

P(x>1152)

At x = 1128

$Z=\frac{1152-1140}{80}$

$Z=0.15$

Refer the z table for p value

P(x<1152)=0.5596

So,P(x>1152)=1-P(x<1152)=1-0.5596=0.4404

Hence the probabilities for the average length of life of the selected batteries is greater than 1152 is 0.4404

C) The average is less than 940.

P(x<940)

At x = 940

$Z=\frac{940-1140}{80}$

$Z=-2.5$

Refer the z table for p value

P(x<940)=0.5596

Hence the probabilities for the average length of life of the selected batteries is less than 940 is 0.5596

7 0

3 years ago

108 = -2(-5 - 7b) What does b equal?

mario62 [17]

Answer:

b = 7

Step-by-step explanation:

108 = -2(-5 - 7b)

Distribute -2 to the terms inside the parenthesis:

108 = 10 + 14b

Subtract 10 from both sides of the equation to isolate 14b:

108 - 10 = 10 + 14b - 10

98 = 14b

Divide 14 on both sides of the equation to solve for b:

$\frac{98}{14} = \frac{14b}{14}$

7 = b

6 0

3 years ago

Which of the following are solutions to the equation below

gavmur [86]

The answers are A and E.
The factors are (2x +9)(2x-9). If you solve each one by equaling each one to zero. You will get:
2x+9=0 2x-9=0
x=-9/2 x=9/2

5 0

3 years ago

Carlos downloaded a pattern from the Internet for making atable with an irregular polygon-shaped top. The instructionson the pat

Nesterboy [21]

From the question;

The longest side of the polygon is 11 in

and the scale factor is 7/2.

Therefore

$\begin{gathered} \text{The longest side of the table = 11in }\times\text{ }\frac{7}{2} \\ \text{The longest side of the table = }\frac{77\text{ in}}{2} \\ \text{The longest side of the table = 38.5 in} \end{gathered}$

Therefore the correct answer is option C

4 0

1 year ago