A heat engine receives heat of 400kW from a heat source of 1100 K, and rejects the waste heat into a heat sink at 320K. It gener
ates 120 kW of power output. Determine the 2nd law thermal efficiency of the heat engine.
1 answer:
Answer:
Explanation:
efficiency of carnot engine operating between 1100 K and 320 K
= 1100 - 320 / 1100
= .709
efficiency of heat engine = 120 / 400 = .30
2 nd law thermal efficiency of heat engine = .30 x 100 / .709
= 42.31 % .
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