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ValentinkaMS [17]
3 years ago
15

Please help me! I got quarantined right when they started a new unit and im confused

Chemistry
1 answer:
Agata [3.3K]3 years ago
6 0
Here are the answers!!!

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Joaq...
MrRa [10]

Answer:

all the statements are true of chemical changes

3 0
2 years ago
Encountering problems during separation/purification is a very common issue in organic synthesis, but these steps are crucial to
Rus_ich [418]
True is the correct answer! your welcome! :)
8 0
3 years ago
Ionic compounds involve a (share, tranfer) of electrons and typically involve atoms that have (Large, similar, very different) e
Juliette [100K]

Answer:

2 Transfer; very different

Explanation:

Ionic compound are compound that are formed from transfer of electron. The cations donate the electron(s) while the anion receive the electron(s). The compound possess a positively charged end and a negatively charge end. Example of ionic compound is NaCl . The sodium donates one electron to the chlorine  to fulfill the octet rule. The sodium atom becomes positively charged  as it donate electron to the chlorine atom. The chlorine atom becomes negatively charged as it receive electron from Sodium atom.

The atoms that are involve in forming ionic compound have very different electronegativity . Electronegativity  is the measure of the ability of an atom to attract a bond pair of electron. For example the NaCl compound, the two atom has verse differences in the electronegativity. Cl atom is far more electronegative than Sodium atom.

6 0
3 years ago
What is the energy transformation in the following:
Tatiana [17]
They all have something to do with electricity
3 0
3 years ago
Given the balanced equation, 2 H2 + O2 -> 2 H2O, answer the following
9966 [12]

Answer: O_2 is the limiting reagent

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{10.0g}{2g/mol}=5.00moles

\text{Moles of} O_2=\frac{20.0g}{32g/mol}=0.625moles

The balanced chemical reaction is :

2H_2+O_2\rightarrow 2H_2O

According to stoichiometry :

1 moles of O_2 require = 2 moles of H_2

Thus 0.625 moles of O_2 will require=\frac{2}{1}\times 0.625=1.25moles of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent as it is present more than the required amount.

8 0
3 years ago
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